anonymous
  • anonymous
HELP ME PLEASE!! A geo sequence t7=192, t12=192 t3= ??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@SithsAndGiggles
anonymous
  • anonymous
@cupcakezz the 7th and 12th terms are the same?
anonymous
  • anonymous
Maybe the common ratio is 1?

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anonymous
  • anonymous
OH SORRY T12=6144 @genius12
anonymous
  • anonymous
mmk A geometric sequence is in the form a, ar, ar^2...ar^(n-1). The seventh term in the given sequence is 192 which we can write as ar^6 = 192. The 12th term is 6144 which we can write as ar^(11) = 6144. Now if we divide both sides of these equations we get: ar^(11) 6144 ------ = ----- ar^6 192 The a's cancel out and this simplifies to: r^5 = 32 Taking the fifth root of both sides we get: r = (32)^(1/5) <-- note that I'm using 1/5 to denote the fifth root of 32. Now we know the common ratio. We now need to solve for 'a'. We can simply plug back in the value of 'r' that we just got in to one of the previous equations we used to find the value of 'a'. I'll plug in 'r' in to t7: t7 = 192 = ar^6 = a[(32)^(1/5)]^6 Which gives: a[(32)^(1/5)]^6 = 192 192 => a = ------------- = 3 [(32)^(1/5)]^6 Now we know both the values of 'a' and 'r'. Now we can find t3. Well t3 is just ar^(3-1) = ar^2. We know a = 3 and r = (32)^(1/5). Just plug them in and find the value :D. @cupcakezz
anonymous
  • anonymous
I got the answer so when you get your answer, tell me and we can check.
anonymous
  • anonymous
Btw I forgot to mention that 32 = 2^5 so we can re-write r = (32)^(1/5) as: r = (32)^(1/5) = (2^5)^(1/5) = 2. Hence r = 2 and we deduced a = 3. Now we have nice looking whole numbers.
anonymous
  • anonymous
did you get 28?
anonymous
  • anonymous
nope.
anonymous
  • anonymous
Remember, a = 3 and r = 2 and t3 = ar^2. Just plug the numbers in..
anonymous
  • anonymous
12!!
anonymous
  • anonymous
can you help me with this one @genius12
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anonymous
  • anonymous
It could be that the sequence is \(ar^n\), and not \(ar^{n-1}\). Or anything else, for that matter. @genius12
anonymous
  • anonymous
@genius12
anonymous
  • anonymous
@SithsAndGiggles wat?
anonymous
  • anonymous
why doesnt sin(x)=2 have no solution? @genius12
anonymous
  • anonymous
@zzr0ck3r ^^ help
anonymous
  • anonymous
|dw:1377548636437:dw|sin(x) has a range of -1 <= y <= 1. It never goes to any number greater than 1 or any number lower than -1.
anonymous
  • anonymous
And create new threads for new questions. Don't ask 10 questions on the same thread.

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