anonymous
  • anonymous
HELP !! Period of y=-20cos(5/3t)+100 ??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@genius12
anonymous
  • anonymous
In radians or degrees?
amriju
  • amriju
do u know the period of cos x?

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anonymous
  • anonymous
degree @KeithAfasCalcLover
anonymous
  • anonymous
I get 216 degrees
anonymous
  • anonymous
Ill show how
anonymous
  • anonymous
Find equation of Sine function with amplitude +5 and period is 240
anonymous
  • anonymous
@KeithAfasCalcLover
anonymous
  • anonymous
Normally, for a formula of the form \[a*cos\big[k(x-d)\big]+c\] has a period of \[\frac{360^\circ}{k}\] So this one has a k value of 5/3 and therefore the period is: \[\frac{360^\circ}{1}/\frac{5}{3}=\frac{360}{1}*\frac{3}{5}=\frac{1080}{5}=\frac{216}{1}=216\]
anonymous
  • anonymous
ok thanks can you help with the second one ?
anonymous
  • anonymous
Haha sure. Sin is similar. Amplitude is the "a" value for the general formula I wrote above. That being said, we also know that the period wich is 360/k needs to be 240 so lets find the k value:
anonymous
  • anonymous
Ill represent period by the symbol \(\lambda\). \[\lambda=\frac{360}{k} \rightarrow 240=\frac{360}{k} \rightarrow 240k=360 \rightarrow k=\frac{360}{240}=1.5\]
anonymous
  • anonymous
Therefore the equation is: \(y=5cos[1.5(x-d)]+c\) where \(c\) and \(d\) are whatever you want them to be! Any number for them will still be correct.
anonymous
  • anonymous
is has to be y=5sin not cos
anonymous
  • anonymous
@KeithAfasCalcLover ^^
anonymous
  • anonymous
Oh hahaha yes correct. Sorry
anonymous
  • anonymous
@KeithAfasCalcLover help with this one
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anonymous
  • anonymous
@genius12 help
anonymous
  • anonymous
OHH this is fun.
anonymous
  • anonymous
OK. Give me a sec.
anonymous
  • anonymous
@cupcakezz i told u for new questions make a new thread. don't post all of them on a single page..
anonymous
  • anonymous
Ah good point haha post it on a new page, tag me and then ill answer

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