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think about 2<3 well -2>-3
I don't understand on Why must you flip the inequality symbol when you divide by a negative number?
let's say you had -x < 2
to solve you could divide both sides by -1 to get x > -2 OR you could add x to both sides to get -x < 2 -x+x < 2 + x 0x < 2 + x 0 < 2 + x then subtract 2 from both sides to get 0 < 2 + x 0 - 2 < 2 + x - 2 -2 < 0 + x -2 < x
notice how if we use the second method, we go from -x < 2 to -2 < x
so that's effectively the sign flipping
"sign flipping" is a method, and is not a valid property of algebra :) if they insist of including it, they should apply it to equalities as well so that you do not have different sets of "rules"
lol I don't think it can be explained any better now you have to think.
where are you stuck GingaTheNinja?
@amistre64 is it not defined for regular equalities? or you can easily defined it that way because = would be the same if we "flip" it?
= flips to = so the process is redundant ... but in order to preserve one set of "rules" it should be included as well.
lol so it basically means that when we divide by negative you have to make it equal???
what do you mean "have to make it equal"?
Why must you flip the inequality symbol when you divide by a negative number?
so you have to divide it too.....
12 > 4 divide both sides by -4, does the sign make sense afterwards?
the "reason" is as Jim described ....
"<" is a binary operation on a well ordered set for convenience, that can be written in a number of different ways
no because -3>-1 is t equal so like I stated before you flip the sign in order to make the situation true
correct, you flip it to retain its "truth" value