anonymous
  • anonymous
find the slope of the secant line for the function f(x)=3x^2-2 passing thru the points (1,1) and (1.1,1.63)
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The slope of the secant line is given by \[slope=\frac{f(1.1)-f(1)}{1.1-1}=\frac{1.63-1}{1.1-1}=\cdots\]
anonymous
  • anonymous
so the slope is 6.3 right
anonymous
  • anonymous
yes

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anonymous
  • anonymous
but the Prof. marked me wrong dont get it.
dumbcow
  • dumbcow
@shark no it is correct, slope of line is 6.3 is question posted correctly...did your teacher want slope of tangent line?
anonymous
  • anonymous
The slope of the secant line
anonymous
  • anonymous
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anonymous
  • anonymous
Use a table to find an approximation, accurate to two decimal places, for \[\lim_{x \rightarrow 2}\frac{2x^2-9x+10 }{ x-2 }\]
anonymous
  • anonymous
can someone pls help me with this
anonymous
  • anonymous
Evaluate the function for values of \(x\) near \(x=2\), such as \(x=2.1,2.01,2.001,...\) that get increasingly nearer. You also have to do it from the other side, meaning evaluate for \(x=1.9,1.99,1.999,...\). You'll notice that both rows/columns (depending on how you construct the table) will either approach the same number, or they will not. In this first case, if both approach the same number, then the limit is this number. In the second, if they don't, then the limit does not exist.
anonymous
  • anonymous
is it approaching -7.00
anonymous
  • anonymous
No, that's not it: http://www.wolframalpha.com/input/?i=%282x%5E2-9x%2B10%29%2F%28x-2%29+when+x%3D2.1%2C2.01%2C2.001%2C1.999%2C1.99%2C1.9 See how for the first three values (2.1,2.01,2.001, all of which are greater than 2) the function is approaching a value of -1? Likewise, for the last three (1.9,1.99, 1.999, all of which are less than 2), the function is approaching -1. Thus the limit is (likely) -1.
anonymous
  • anonymous
thank really appreciate it, i was doing it wrongly.
anonymous
  • anonymous
np
anonymous
  • anonymous
Suppose that the graph of y=f(x) is Determine whether the limit exists when x=1 and x=-1. If it does not exist, enter DNE in the space provided. find \[\lim_{x \rightarrow 1}f(x)\] find \[\lim_{x \rightarrow -1} f(x)\]
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