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n+1/3n=2n+10 solve for n
idk how to solve it w/the 1/3??? what do I do first on left side????
You could start by finding the common denominator for all terms.
6 or 20?
Out of those two 6 would work the best, but 3 would probably your best choice.
how would iine?????
You multiply each of your terms by 3/3 except for your 1/3n term because it already has a denominator of 3.
3/3 multiply by 2n and 10 too?????????
\[3/3(n+1n/3=2n+10)\] \[3n/3 + n/3=6n/3+30/3\]
Exclude the 1n/3 term in that distribution
that's what I got, is it correct??
Could you show me how you got that?
Where is your 2n term?
so the number is 10+6n ?????
3n/3+n/3=6n/3+30/3 We could distibute a 3 to each of these terms so that they are no longer fractions. 3(3n/3+n/3=6n/3+30/3) 3n+n=6n+30
and that equation might be easier to solve
I got N=2n+30
Can I ask where your getting the "N" in N=2n+30
Does N represent zero?
oh yeah my bad/:
If that is the case then your previous response "N=2n+30" is correct but still needs to be solved
the number is 15 ????
mind helping w/afew more pleaseeee???????????????
2-4 dif but similar on back
2.) separate 104 into two parts so that one part is 18 more than the other part. find each part???? @Tauist628
104 split in two n+18 and n so 2n+18=104, solve for n
I got N=43
I got N=43 @Tauist628
but theres more than one unknown how do I find the 2nd unknown???? @Tauist628
If you know what N is, then you should substitute it in for the equation of your 2nd unknown, N+18
3 last qustions????
Do they all have the same basic concept for solving them?
yeah but 10-13 look harder
Let's work them out together and such
10.)the sm of the ages of Ruth and her mother is 75 years. The difference in their age is 29 years. how old is each?????? 11.) The sum of $180 was divided amoung 3 people so that the second person recievd $6 less than twice as much as te first, and the third received $7 more than the second. how much did each person receive????? 12.) The sum f $305 was divided among 3 people so that the secon received $4 ess than twice as much as the first, and the thirdrecieved $23 more than the second. HOW much did each person receive?????? 8.) Stanley worked 6 more than twice as many hou as Kathleen did.. How many hours did each work if tgether they worked 69 hours??????
10.) A system of equations should be set up. r+m=75 and m-r=29
Solve for either variable Ex r=75-m or m=75-r for your first equation and m=29+r or r=m-29
what number?????? @Tauista628
What do you mean "what number"?
what number was u even talking about??? ur last comment?
OH, which question? I was doing question #10
can u repeat whaever u said please?
10.) A system of equations should be set up. r+m=75 and m-r=29 Solve for either variable Ex r=75-m or m=75-r for your first equation and m=29+r or r=m-29
how do u solve m=29+r?
You plug into the original equation r+m=75 substitue "m" with (29+r) r+(29+r)=75
solve for r
I got r^2=75/29 ???
You're not distributing the r, you're just adding r+(29+r)=r+r+29
don't get it please help asap after this one I gtg
ilike help on 11 and 12 if u can???? tho,
r+r+29=75 2r+29=75 2r=46 r=23 Substitute this back in for your first equation m+r=75 m+23=75 m=52 so Ruth's age is 23 and her mother's age is 52
Could those be done at another time?
pleaseeee if u don't mind I could really use the help due tom. pleaseee
I thought you said you had to go.
yeah I got yelled at for being up at ten but have to finish my homework.. mind help????
Okay could you retype #11 so I won't have to scroll as much
11) the sumof $180 was divided among 3 people so that tcond perso received $6 less than twice as much as the first, and received $7 more than the secd. How much did each person receive?????
PLease help ASAP
I can't read the question very well. Which person is which?
second person $6
180=(2n-6)+(n-7)+n 180=4n-13 solve for n
now plug n in for your original equations 2n-6=2nd Person n-7=3rd Person n=1st Person
2(48.25)-6=Money given to 2nd person 48.25-7=Money given to 3rd person 48.25=money given to first person
ok thanks.. can u scroll up for 12 please????
12.) The sum f $305 was divided among 3 people so that the secon received $4 ess than twice as much as the first, and the thirdrecieved $23 more than the second. HOW much did each person receive?????? Same concept 305=(2n-4)+(2n-4+23)+n 305=5n+15 290=5n solve for n then substitute back into your original equations 2(n)-4=Money given to 2nd person 2(n)-4+23=Money given to 3rd person (n)=Money given to 1st person
290=5n n=58 substitute back in 2(58)-4=Money to 2nd person 2(58)+19=Money to 3rd person 58=Money to 1st person Also, don't forget to put your labels
that's it..thanks soooo much
I would like to advise to make sure for #11 that each person is getting the correct corresponding value as I wasn't able to accurately tell which was which.
If you ever need anymore help feel free to send a message and I'll help as much as I can. Bye