someone help?

- anonymous

someone help?

- Stacey Warren - Expert brainly.com

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- schrodinger

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- anonymous

Find the exact value of the radical expression in simplest form.
\[c \sqrt{c}+12c \sqrt{c}-2c \sqrt{c}\]

- zepdrix

|dw:1377565640336:dw|

- zepdrix

It's just an apple :O Add up all of your apples.

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## More answers

- anonymous

If you have like radicals \[\Large \sqrt{c}\] then you can add them together

- anonymous

3 apples

- zepdrix

3? +_+

- dan815

lol

- dan815

hahahaha

- anonymous

4

- anonymous

sorry i thought i pressed 4

- zepdrix

1 apple + 12 apples - 2 apples = ?

- anonymous

11

- zepdrix

ya that sounds right :)\[\Large 11(apples) \qquad=\qquad 11c\sqrt c\]

- dan815

|dw:1377565818490:dw|

- zepdrix

I like my apple method better -_- lol

- anonymous

Find the exact value of the radical expression in simplest form.
\[\sqrt{11}+2\sqrt{11}\]

- dan815

its a good method im just throwing out some other ways to think bout it

- zepdrix

Same type of idea sav :D don't let the funky looking radical confuse you.
It's just a piece of fruit...
So you have 1(thing) + 2(things) = ?

- anonymous

3(things)?

- zepdrix

Yay :D\[\Large 3(things) \qquad=\qquad 3\sqrt{11}\]

- zepdrix

Because sqrt{11} was our "thing"

- anonymous

Find the exact value of the radical expression in simplest form.
\[\sqrt{144}-\sqrt{40}-\sqrt{10}\]

- zepdrix

Are you allowed to use a calculator?
It might be a good idea to first check and see if any of them are perfect squares.
What I mean by that is ~ Punch in sqrt{144}, if it gives you no decimal value, then it's a perfect square.
Check them if you don't remember which numbers are perfect squares :D

- anonymous

is it \[3\sqrt{10}\]

- zepdrix

No. But that will be `part of` our answer.

- anonymous

\[12-3\sqrt{10}\]???

- zepdrix

Lol now you're just cheating :) reading your multiple choice answers without trying.
Silly girl :3

- anonymous

no i did it on my calculator it said 3

- dan815

lol

- anonymous

can u not

- dan815

do you want me to do this course for you?

- dan815

10 dolla

- anonymous

im not paying you to do my course

- dan815

1 dolla?

- anonymous

no

- zepdrix

\[\large \sqrt{40} \qquad=\qquad \sqrt4\cdot\sqrt{10} \qquad=\qquad 2\sqrt{10}\]
\[\Large \sqrt{144}\color{royalblue}{-\sqrt{40}-\sqrt{10}}\quad=\quad \sqrt{144}\color{royalblue}{-2\sqrt{10}-\sqrt{10}}\]

- zepdrix

This would be our first step in solving it.
I used the first line to change the blue part.

- zepdrix

no dolla? :c

- zepdrix

but but but +_+

- anonymous

hahahah no.

- anonymous

i cant pay u

- zepdrix

ik ik i jk c:

- anonymous

so it isnt any of the options i said?

- zepdrix

\[\Large \sqrt{144}\color{royalblue}{-2\sqrt{10}-\sqrt{10}}\]Solve it from there girl +_+

- anonymous

its still like 3

- zepdrix

Yes it's "like" 3.. it's around 3.. but you to do the algebra D: not just calculuator fun

- zepdrix

you need*

- anonymous

im not even active in this class im just re doing tests to make the grade better. I dont remember any of this

- zepdrix

Oh boy that sucks :O

- anonymous

thats why i came on here!

- zepdrix

sav you so cray :Y

- anonymous

hahahahahah why

- zepdrix

cuz you so lazy XD lol
put in a little effort lady! :3 Sheesh!

- anonymous

i dont need to though. i cant even access anything to learn it i just need to test answers

- zepdrix

Think about your future though D:
What's gonna happen when you head to the grocery store and need to buy 2 square roots of 10, but then you need to return 1 square root of ten because it's defective?
What's gonna happen?? You're gonna think to yourself, "Oh no!! I shoulda learned about those squares of 10!!! :O"

- anonymous

seriously.........

- anonymous

k ill ask someone else

- zepdrix

k XD

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