anonymous
  • anonymous
Someone help?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Find the exact value of the radical expression in simplest form. \[\sqrt{144}-\sqrt{40}-\sqrt{10}\]
anonymous
  • anonymous
\[\sqrt{144}-\sqrt{40}-\sqrt{10}=\sqrt{12*12}-\sqrt{2*2*10}-2\sqrt{10}=12-2\sqrt{10}-2\sqrt{10}\] i think now you can solve.
anonymous
  • anonymous
correction Replace 2sqrt{10} by sqrt{10} at the end.

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More answers

anonymous
  • anonymous
i cant even see it all
anonymous
  • anonymous
i think only answer is to be written.
anonymous
  • anonymous
does the answer have a 3 in it anywhere
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay is it \[3\sqrt{10} or 12-3\sqrt{10}\]
anonymous
  • anonymous
\[12-3\sqrt{10}\]
anonymous
  • anonymous
I KNEW IT!!! someone told me that wasnt it
anonymous
  • anonymous
it is simple we have to add the terms with the same sign under radical sign and subtract if they are of different sign.
anonymous
  • anonymous
Can you maybe do a problem for me and write it out
anonymous
  • anonymous
\[5+4\sqrt{3}-3\sqrt{3}-2\sqrt{3}+5\sqrt{3}+3\sqrt{2}-4\sqrt{2}-3\] \[=\left( 5-3 \right)+\left( 4\sqrt{3}+5\sqrt{3} \right)-\left( 3\sqrt{3}+2\sqrt{3} \right)+\left( 3\sqrt{2}-4\sqrt{2} \right)\] \[=2+9\sqrt{3}-5\sqrt{3}-\sqrt{2}=2+4\sqrt{3}-\sqrt{2}\]
anonymous
  • anonymous
have you followed.
anonymous
  • anonymous
yes!!
anonymous
  • anonymous
but like i would give you the problem lol can u do it ?
anonymous
  • anonymous
surely
anonymous
  • anonymous
Nakim simplified: \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18}\] and got \[-10\sqrt{2x}\] for an answer. Part 1: Using complete sentences, explain what Nakim did wrong. Part 2: Show all your work to simplify the expression.
anonymous
  • anonymous
\[3\sqrt{2x}+x \sqrt{2*2*2x}-5\sqrt{3*3*2}\] \[3\sqrt{2x}+2x \sqrt{2x}-5*3\sqrt{2}=\left( 3+2x \right)\sqrt{2x}-15\sqrt{2}\]
anonymous
  • anonymous
it said using complete sentences:)
anonymous
  • anonymous
??
anonymous
  • anonymous
nakim took (3+2x) as (3+2)=5 as he missed x
anonymous
  • anonymous
also he took \[\sqrt{2} as \sqrt{2x}\]
anonymous
  • anonymous
we have to add like terms under the same radical sign he wrote 3+2 in place of 3+2x and then subtracted 15 3+2=5-15=-10
anonymous
  • anonymous
thank you all very much :)
anonymous
  • anonymous
u r welcome

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