anonymous
  • anonymous
Find an equation of the horizontal line that passes through (-4, -3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
horizontal line looks like \(y=\text {some number}\) in this case it seems to be that \(\text{some number}=-3\)
anonymous
  • anonymous
I'm still not getting it. I need an equation to help me.
anonymous
  • anonymous
Sorry.

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dan815
  • dan815
|dw:1377568379112:dw|
dan815
  • dan815
a horizontal line has slope = ?
anonymous
  • anonymous
So you're basically saying that the line passes through -3. That would basically be the slope right?
dan815
  • dan815
a horizontal has no slope
dan815
  • dan815
a horizontal line*
anonymous
  • anonymous
Thank you. @dan815
dan815
  • dan815
you know the equation y=mx+b
anonymous
  • anonymous
Yes.
dan815
  • dan815
so what did you get as the answer
anonymous
  • anonymous
So far I've plugged in y= m(-3)+ (-4) but I doubt I did it correctly. I am not sure.
dan815
  • dan815
what is your m in this case
anonymous
  • anonymous
Like you said, a horizontal line has no slope. Wouldn't it be 0?
dan815
  • dan815
ok
dan815
  • dan815
so your equation is?
anonymous
  • anonymous
Like you said, a horizontal line has no slope. Wouldn't it be 0?
dan815
  • dan815
okay so tell me the equation
dan815
  • dan815
if someone asked you what is the equation of this line... what are you going to tell them
anonymous
  • anonymous
Here's what I did. y= 0(-3) - 4 y= 0-4 y= -4 I did it wrong. Idk how.
dan815
  • dan815
okay so y = -4 is your equation ?
anonymous
  • anonymous
No it's supposed to be -3
anonymous
  • anonymous
But I don't know how
dan815
  • dan815
yes it is..
dan815
  • dan815
okay we should probably start at square one
anonymous
  • anonymous
Okay.
dan815
  • dan815
try to understand what is going on clearly
dan815
  • dan815
first of all (-4,-3) what does this mean?
anonymous
  • anonymous
-4 is x and -3 is y
dan815
  • dan815
okay good
dan815
  • dan815
|dw:1377569096032:dw|
dan815
  • dan815
so you have this point
anonymous
  • anonymous
Yes.
dan815
  • dan815
now you have a horizontal line passing through this point
dan815
  • dan815
|dw:1377569152236:dw|
dan815
  • dan815
what is the y intercept
anonymous
  • anonymous
y intercept is -3
dan815
  • dan815
okay so you have the equation y = mx + b
dan815
  • dan815
what does that b stand for?
anonymous
  • anonymous
The b stands for y-intercept. So what I've done so far is that I instead put in y= 0(-3) - 3 = y= -3
dan815
  • dan815
ok
anonymous
  • anonymous
My mistake, I did -3 = 0 (-4) -3. -3= 0-3, and then -3 = -3
dan815
  • dan815
ok..
dan815
  • dan815
but your equation is y = -3 right
anonymous
  • anonymous
yes.
dan815
  • dan815
makes sense, right, all it is is saying is its y= -3 the x value doesnt matter
anonymous
  • anonymous
if you don't mind me saying so, this is correct but way way too much work the horizontal line through \((a,b)\) is given by the equation \(y=b\)
anonymous
  • anonymous
Now I get it! The x value doesn't matter. That's what I also needed to know. Meaning I don't add in the x value.
dan815
  • dan815
if i told you to draw the line x = 2 what would that look like
anonymous
  • anonymous
A vertical line plotted on x= -2
dan815
  • dan815
a vertical line plotted through (-2,y), y can be any value
dan815
  • dan815
oh wait lol where did that -2 come from
dan815
  • dan815
nevermind that stuff, you get the point
anonymous
  • anonymous
Yep, indeed I do. Thanks very much for the help! :)
dan815
  • dan815
okay just do more research look up line explainations and stuff on youtube
dan815
  • dan815
you need to understand lines in many different ways, its one of the fundamentals thing in math, a lot of stuff will be built on this
anonymous
  • anonymous
Yeah. I should. The book doesn't explain it enough. Just the slope has been given despite reading the section numerous times.
dan815
  • dan815
basically a line, is representing a form of linear relationship data
dan815
  • dan815
like say you have a table
dan815
  • dan815
|dw:1377569940276:dw|
dan815
  • dan815
there are so many points i can keep writing, that is too much work
dan815
  • dan815
but if i can form a picture of it, in my head or be able to draw a picture to represent this data, that will be a lot faster and easier to look at
dan815
  • dan815
right
anonymous
  • anonymous
Yes. It makes it easier
dan815
  • dan815
|dw:1377570027754:dw|
anonymous
  • anonymous
Yeah.
dan815
  • dan815
whats the equation?
dan815
  • dan815
look at that data
dan815
  • dan815
what ever x is, y value is that also right..
anonymous
  • anonymous
Yes since they are the same values
dan815
  • dan815
sooo the equation is?
dan815
  • dan815
you gotta start thinking equations
dan815
  • dan815
how can i represent all this data with some simple equation?
dan815
  • dan815
|dw:1377570294731:dw|
dan815
  • dan815
y = ?
anonymous
  • anonymous
(2,2) for example, that would be y= 2 since plotted, 2 is the intercept
dan815
  • dan815
forget lines right now.. im talking about something before that more basic
dan815
  • dan815
what is going on in this table of data
dan815
  • dan815
im not asking you anything tricky dont get confused
dan815
  • dan815
|dw:1377570461032:dw|
dan815
  • dan815
take a look at this data.. when x is 0 y is 0 when x is 1 y is 1 whatever x is y is that
dan815
  • dan815
how do i say that in math now
dan815
  • dan815
how do i say whatever x is, y is also that

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