anonymous
  • anonymous
I am stuck with this question cant decide! Which of the following statements is true if ray BE is a bisector of angle CBA? (Points : 3) EBD is congruent to DBA. Ray BE is a bisector of angle ABE. EBD is congruent to CBE. Ray BD is a bisector of angle CBA.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Here the angle
anonymous
  • anonymous
Hello
anonymous
  • anonymous
I was think if its eith option A. or option D

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More answers

anonymous
  • anonymous
thinking*
anonymous
  • anonymous
Those two are kinda close i think but i cant decide witch is it?
dan815
  • dan815
dont worry im here I KNOW THE ANSWER
anonymous
  • anonymous
Thanks so much!
dan815
  • dan815
THE answer has been bestowed upon me
anonymous
  • anonymous
first of all, the first statement is correct.
anonymous
  • anonymous
So Option A is correct
anonymous
  • anonymous
yes. your option B is incorrect.
anonymous
  • anonymous
Option B?
anonymous
  • anonymous
I thought i was Option A?
anonymous
  • anonymous
well, the second statement. the third one is also incorrect.
anonymous
  • anonymous
I said INcorrect.
anonymous
  • anonymous
So witch one should i chose?
dan815
  • dan815
|dw:1377572034244:dw|
dan815
  • dan815
this is what an angle bisector does bisects the angle in 2 equal halves
anonymous
  • anonymous
everything else is false except for the first one.
anonymous
  • anonymous
So option A witch is EBD is congruent to DBA.
anonymous
  • anonymous
yes.
dan815
  • dan815
so lets see now if dba = 30 |dw:1377572145225:dw|
anonymous
  • anonymous
Thanks for the angle dan
dan815
  • dan815
GIMME MEDAL :)
anonymous
  • anonymous
So option A is correct Cause when i use thr graph you get me i got option A
dan815
  • dan815
yeah
anonymous
  • anonymous
Ok ill give you one :D
anonymous
  • anonymous
Would you like more
anonymous
  • anonymous
Cause i need help with 7 more
anonymous
  • anonymous
So i can give you 7 medals
dan815
  • dan815
ok
anonymous
  • anonymous
I promise it wont be you doing all the work
dan815
  • dan815
you should be able to do some on your own now, if u understand this stuff
anonymous
  • anonymous
Alright ill open a new post
dan815
  • dan815
ok

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