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DO you have a picture?
we need to draw the picture based on the description and prove
yep i have one but how to insert it |dw:1377587687555:dw|
that's the figure you were given?
Nincompoop, make sure P and Q are the at the middle of the circle. Maybe that would help?
yes this is the fig but it is not neat
that's what I was trying to draw, so I was a little confused when you put up your own figure… well it's intersecting… LOL |dw:1377588177376:dw|
nincompoop's is wrong
ya like the second one
Yeah, the red circles should be right
kawaii's is right
Thats what I thought........
if the circle has the same area or perimeter then all sides of the triangle are equal. that's the only condition
I don't understand anything besides Greek Alphabet and English Alphabet, man Don't show me sanskrit-looking scribbles LOL
no under that it is written in english
it is written in two languages
She got that terrorist homework.
ohhhh I see! LOL kawaii you're messed up
NO WE WILL NOT HELP YOU DEVELOP THE NEXT BOMB!
well to prove that PQ=RQ=PR like I said that in that figure we assume that the circles are identical and any distance from the center of a circle represents the radius, and all segments from the center (radius) are equidistant. since each segment (radius) is represented by P, Q and R we have the following demonstration: PR = r RQ = r PQ = r r = r = r ∴PQ=RQ=PR I don't know the jargons yet. but this should suffice if you want you can wait until I finish my analytical geom to finis this up.
Circle got this I think… LOL it's written in his/her name
Actually, the question is not really complete, because it also needs to state that both circles have equal radii. Assuming the radius of both circles is RAD, then you know that the distance from the center of such a circle to the circle itself is by definition RAD. All lengths, PQ, QR and PR are either on centers or on the circles itself so all these distances need to be equal to RAD and hence have the same length. Hope this helps...
@nincmpoop....seems you've said the same thing, my apologies for duplicating
ya thank yuuuuuuuuuuuuuuu
so PQ AND QP R THE RADII OF THE CIRCLES Q AND P. EVEN PR AND QR ARE THE RADII OF THE CIRCLES THUS IT IS PROVED
NO. PQ does not represent a circle. Just the centers of an intersecting identical circles which make up a diameter PQ
since diameter = 2r the rest follows
don't use short language like "r" and "u" when referring to "are" and "you" they are troublesome to read specially when dealing with geometry