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raebaby420
 one year ago
Please Help c:
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10
(−4, −2) and (2, 5)
(−2, −4) and (2, 5)
(−2, −4) and (5, 2)
No Real Solutions
raebaby420
 one year ago
Please Help c: What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

This Question is Closed

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0What is the solution to the following system of equations? y = x2 + 10x + 11 y = x2 + x − 7 (−2, −5) (2, −5) (−2, 5)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4rewrite the 2nd equation with y as the subject y = 8x  10 now equate it to the 1st equation and you get \[8x  10 = x^2 + 12x + 10\] now you have 1 equation in 1 unknown to solve

myko
 one year ago
Best ResponseYou've already chosen the best response.0y = x2 + 12x + 30 8x − y = 10 express y from second equation: \(y=8x10\) substitute in the 1º equation: \(8x10=x^2 + 12x + 30\) rearange terms: \(x^2+4x+40=0\) solve this. You will get 2 solutions, which later substitute in the 2º equation to get corresponding y value

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4oops should be ' \[8x  10 = x^2 + 12x + 30\] just solve for x

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Mm.. ill try. One sec, ill let you know what I get

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4and can you check your equations as they may be a typo in them...

nirmalnema
 one year ago
Best ResponseYou've already chosen the best response.0you can get the ans by by making the quadratic eq..in x

missMob
 one year ago
Best ResponseYou've already chosen the best response.0we will put all the x on one side

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4because based on the information there are any solutions that are real numbers

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4oops... which is an option

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Ok.. so its D.. cool

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0But idk how to get D

missMob
 one year ago
Best ResponseYou've already chosen the best response.0*takes out the gun shoots maths*

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well do you know about the discriminant...? thats how you check...

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0No.. but I got 8x10=x2+12x+30 so far..

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0What do I do from there?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4subtract 8x from both sides... then add 10 to both sides of the equation...

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Oh.. I knew that. For some reason I thought I needed to bring my X from the right to the left.

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Ok.. so I got x=x2+4x+40 Is that right?

nirmalnema
 one year ago
Best ResponseYou've already chosen the best response.0ya you got it right

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4and the discriminant is for a quadratic \[ax^2 + bx + c = 0\] thew discriminant is \[b^2  4ac\] you have a = 1, b = 4 and c = 40 it will be less than zero... meaning complex roots

raebaby420
 one year ago
Best ResponseYou've already chosen the best response.0Thanks everyone! c:
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