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anonymous
 3 years ago
Please Help c:
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10
(−4, −2) and (2, 5)
(−2, −4) and (2, 5)
(−2, −4) and (5, 2)
No Real Solutions
anonymous
 3 years ago
Please Help c: What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the solution to the following system of equations? y = x2 + 10x + 11 y = x2 + x − 7 (−2, −5) (2, −5) (−2, 5)

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5rewrite the 2nd equation with y as the subject y = 8x  10 now equate it to the 1st equation and you get \[8x  10 = x^2 + 12x + 10\] now you have 1 equation in 1 unknown to solve

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y = x2 + 12x + 30 8x − y = 10 express y from second equation: \(y=8x10\) substitute in the 1º equation: \(8x10=x^2 + 12x + 30\) rearange terms: \(x^2+4x+40=0\) solve this. You will get 2 solutions, which later substitute in the 2º equation to get corresponding y value

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5oops should be ' \[8x  10 = x^2 + 12x + 30\] just solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Mm.. ill try. One sec, ill let you know what I get

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5and can you check your equations as they may be a typo in them...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can get the ans by by making the quadratic eq..in x

missMob
 3 years ago
Best ResponseYou've already chosen the best response.0we will put all the x on one side

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5because based on the information there are any solutions that are real numbers

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5oops... which is an option

missMob
 3 years ago
Best ResponseYou've already chosen the best response.0*takes out the gun shoots maths*

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5well do you know about the discriminant...? thats how you check...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No.. but I got 8x10=x2+12x+30 so far..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do I do from there?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5subtract 8x from both sides... then add 10 to both sides of the equation...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh.. I knew that. For some reason I thought I needed to bring my X from the right to the left.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok.. so I got x=x2+4x+40 Is that right?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.5and the discriminant is for a quadratic \[ax^2 + bx + c = 0\] thew discriminant is \[b^2  4ac\] you have a = 1, b = 4 and c = 40 it will be less than zero... meaning complex roots
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