A community for students.
Here's the question you clicked on:
 0 viewing
raebaby420
 2 years ago
Please Help c:
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10
(−4, −2) and (2, 5)
(−2, −4) and (2, 5)
(−2, −4) and (5, 2)
No Real Solutions
raebaby420
 2 years ago
Please Help c: What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

This Question is Closed

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0What is the solution to the following system of equations? y = x2 + 10x + 11 y = x2 + x − 7 (−2, −5) (2, −5) (−2, 5)

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5rewrite the 2nd equation with y as the subject y = 8x  10 now equate it to the 1st equation and you get \[8x  10 = x^2 + 12x + 10\] now you have 1 equation in 1 unknown to solve

myko
 2 years ago
Best ResponseYou've already chosen the best response.0y = x2 + 12x + 30 8x − y = 10 express y from second equation: \(y=8x10\) substitute in the 1º equation: \(8x10=x^2 + 12x + 30\) rearange terms: \(x^2+4x+40=0\) solve this. You will get 2 solutions, which later substitute in the 2º equation to get corresponding y value

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5oops should be ' \[8x  10 = x^2 + 12x + 30\] just solve for x

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0Mm.. ill try. One sec, ill let you know what I get

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5and can you check your equations as they may be a typo in them...

nirmalnema
 2 years ago
Best ResponseYou've already chosen the best response.0you can get the ans by by making the quadratic eq..in x

missMob
 2 years ago
Best ResponseYou've already chosen the best response.0we will put all the x on one side

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5because based on the information there are any solutions that are real numbers

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5oops... which is an option

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0Ok.. so its D.. cool

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0But idk how to get D

missMob
 2 years ago
Best ResponseYou've already chosen the best response.0*takes out the gun shoots maths*

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5well do you know about the discriminant...? thats how you check...

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0No.. but I got 8x10=x2+12x+30 so far..

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0What do I do from there?

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5subtract 8x from both sides... then add 10 to both sides of the equation...

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0Oh.. I knew that. For some reason I thought I needed to bring my X from the right to the left.

raebaby420
 2 years ago
Best ResponseYou've already chosen the best response.0Ok.. so I got x=x2+4x+40 Is that right?

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.5and the discriminant is for a quadratic \[ax^2 + bx + c = 0\] thew discriminant is \[b^2  4ac\] you have a = 1, b = 4 and c = 40 it will be less than zero... meaning complex roots
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.