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raebaby420

  • one year ago

Please Help c: What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

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  1. raebaby420
    • one year ago
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    What is the solution to the following system of equations? y = x2 + 10x + 11 y = x2 + x − 7 (−2, −5) (2, −5) (−2, 5)

  2. campbell_st
    • one year ago
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    rewrite the 2nd equation with y as the subject y = 8x - 10 now equate it to the 1st equation and you get \[8x - 10 = x^2 + 12x + 10\] now you have 1 equation in 1 unknown to solve

  3. myko
    • one year ago
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    y = x2 + 12x + 30 8x − y = 10 express y from second equation: \(y=8x-10\) substitute in the 1º equation: \(8x-10=x^2 + 12x + 30\) rearange terms: \(x^2+4x+40=0\) solve this. You will get 2 solutions, which later substitute in the 2º equation to get corresponding y value

  4. campbell_st
    • one year ago
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    oops should be ' \[8x - 10 = x^2 + 12x + 30\] just solve for x

  5. raebaby420
    • one year ago
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    Mm.. ill try. One sec, ill let you know what I get

  6. missMob
    • one year ago
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    :O maths

  7. campbell_st
    • one year ago
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    and can you check your equations as they may be a typo in them...

  8. nirmalnema
    • one year ago
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    you can get the ans by by making the quadratic eq..in x

  9. missMob
    • one year ago
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    we will put all the x on one side

  10. raebaby420
    • one year ago
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    The what? LOL

  11. campbell_st
    • one year ago
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    because based on the information there are any solutions that are real numbers

  12. campbell_st
    • one year ago
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    oops... which is an option

  13. campbell_st
    • one year ago
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    sorry...

  14. raebaby420
    • one year ago
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    Ok.. so its D.. cool

  15. missMob
    • one year ago
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    maths is confusing

  16. raebaby420
    • one year ago
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    But idk how to get D

  17. missMob
    • one year ago
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    *takes out the gun shoots maths*

  18. campbell_st
    • one year ago
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    well do you know about the discriminant...? thats how you check...

  19. raebaby420
    • one year ago
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    lol...

  20. raebaby420
    • one year ago
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    No.. but I got 8x-10=x2+12x+30 so far..

  21. raebaby420
    • one year ago
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    What do I do from there?

  22. campbell_st
    • one year ago
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    subtract 8x from both sides... then add 10 to both sides of the equation...

  23. raebaby420
    • one year ago
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    Oh.. I knew that. For some reason I thought I needed to bring my X from the right to the left.

  24. raebaby420
    • one year ago
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    Ok.. so I got x=x2+4x+40 Is that right?

  25. nirmalnema
    • one year ago
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    ya you got it right

  26. campbell_st
    • one year ago
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    and the discriminant is for a quadratic \[ax^2 + bx + c = 0\] thew discriminant is \[b^2 - 4ac\] you have a = 1, b = 4 and c = 40 it will be less than zero... meaning complex roots

  27. raebaby420
    • one year ago
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    Sooo its D.

  28. raebaby420
    • one year ago
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    Thanks everyone! c:

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