Please Help c: What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

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What is the solution to the following system of equations? y = x2 + 10x + 11 y = x2 + x − 7 (−2, −5) (2, −5) (−2, 5)

rewrite the 2nd equation with y as the subject y = 8x - 10 now equate it to the 1st equation and you get \[8x - 10 = x^2 + 12x + 10\] now you have 1 equation in 1 unknown to solve

y = x2 + 12x + 30 8x − y = 10 express y from second equation: \(y=8x-10\) substitute in the 1º equation: \(8x-10=x^2 + 12x + 30\) rearange terms: \(x^2+4x+40=0\) solve this. You will get 2 solutions, which later substitute in the 2º equation to get corresponding y value

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