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y = (x)^2 y = -(x)^2 , reflects y = -2(x)^2, this makes things longer in the vertical so im leary of the vertical "compression"; but then im out of date with the terminology y = -2(x+1)^2 , left by 1 y = -2(x+1)^2+4 , up by 4
vertical stretch does seem more appropriate http://regentsprep.org/Regents/math/algtrig/ATP9/funclesson1.htm
thank you so much for helping!
so when is it verticle stretch or compression? ):
that's where I get confused
when we multiply by some constant whose absolute value is greater than 1 |-2| > 1 we are moving the points further away from the x axis. y=x; when x=1, y=1 y=2x; when x=1, y=2 y=2 is further away from the x axis then y=1
when we mutiply by a constant that is a proper fraction; we are essentially dividing ... and lessening the distance
y=x, when x=1, y=1 y=1/2 x, when x=1, y=1/2 notice that y=1/2 is closer to the x axis than y=1
compression is moving things closer, stretching moves them further away ..
so... than this problem is compression, no? .__.
compare it: y = x^2 y = -2x^2 for any value of x (other than 0 in this case), how does that effect the y value?
.... D: idk :(
the closer it is to 1, the skinnier the graph gets?
so .25x^2 would be compression because it's less than 1 and really skinny,
which would be verticle expansion
because it opens up more???? ._<
would -2(x+2)^3+1 be a vertical expansion as well?
yes, that would be a vertical expansion ... its stretching the graph away from the x axis by a factor of |-2|
thanks, i get it now :)