anonymous
  • anonymous
Given the following chemical equation, if 50.1 grams of silicon dioxide is heated with excess carbon and 32.3 grams of silicon carbide is produced, what is the percent yield for this reaction? SiO2 (s) + 3C (s) arrow SiC (s) + 2CO (g) Answer 97% 75% 103% 48% I believe this is 97, am I correct?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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aaronq
  • aaronq
can you show your work?
anonymous
  • anonymous
hold on wrong work! lol
aaronq
  • aaronq
haha ok. i just wanna see your thought process ..and that you're not actually just guessing.

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More answers

anonymous
  • anonymous
I thought it was 96 but checking back over my work I'm not sure - I think i made some errors. I know that the total mass of reactants = 60 + 36 = 96 grams
anonymous
  • anonymous
Because of that I presumed it would be 97% as that's closed but I realize I need to calculate the percent of yield. @aaronq
aaronq
  • aaronq
that's not how you do it.. at all :P you need to convert the amounts in grams given to moles. moles=\(\dfrac{m}{M}\) then use the stoichiometric coefficients to build a ratio: SiO2 (s) + 3C (s) arrow SiC (s) + 2CO (g), \(\dfrac{n_{SiO_2}}{1}=\dfrac{n_{SiC}}{1}\) since they're both 1, we can just say that the moles are equal. SO, to find the percent yield, you divide the moles (or grams) actually produced, by the theoretical yield times 100%. percent efficiency = \(\dfrac{mass \;obtained}{theoretical\; mass}*100\%\)
chmvijay
  • chmvijay
did u get it ? @Pumpkin890
chmvijay
  • chmvijay
can u tell me molar mass of SIO2 and SiC
anonymous
  • anonymous
Mass obtained? Would 50.1 be mass obtained and theoretical mass be 32.3?
chmvijay
  • chmvijay
nope :(
anonymous
  • anonymous
60.08 g/mol = SIO2 40.11 g/mol SiC
anonymous
  • anonymous
For the molar masses @chmvijay
chmvijay
  • chmvijay
ok now 60.08 gram SIO2 should produce 40.11 gram of SiC right according to equation but 50.1 gram of SiO2 should give = 40.11*50.1 /60.08= 33.44 gram of SIC but its forming only about 32.3 gram? can u solve now
anonymous
  • anonymous
percent efficiency = 33.44/ 32.2 ∗100% Is that right?
anonymous
  • anonymous
Ah! 103! Answer choice C Thank you @chmvijay
chmvijay
  • chmvijay
noo for 33.44 ----->100 for 32.3 gram=100*32.3/33.44 =
anonymous
  • anonymous
oOH OKAY. one more time here..
chmvijay
  • chmvijay
LOL

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