anonymous
  • anonymous
Simplify: square root x^3y^2 4square root xy^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1377624500648:dw|
anonymous
  • anonymous
There isn't a sign in between
anonymous
  • anonymous
The book says the answer is 7/x^4 7/y^4 but I don't understand how to get that

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More answers

anonymous
  • anonymous
Is this what you question looks like? \(\sqrt{x^3y^2} 4\sqrt{xy^3}\) If so, the lack of operation sign between the terms implies multiplication.
anonymous
  • anonymous
yes that's what it looks like
anonymous
  • anonymous
Are you sure of the answer? That is not what I got.
anonymous
  • anonymous
That is the answer in the back of the book
anonymous
  • anonymous
You might want to verify that you looked at the correct number. Or maybe it is a misprint. What answer did you get?
anonymous
  • anonymous
I don't understand how to find the answer
jdoe0001
  • jdoe0001
hmmmm, can you give us a screenshot of it ?
anonymous
  • anonymous
the answer or the problem?
jdoe0001
  • jdoe0001
the problem
anonymous
  • anonymous
number 7
1 Attachment
jdoe0001
  • jdoe0001
hmmm, it has to be multiplication then
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1377625945927:dw|
jdoe0001
  • jdoe0001
\(\bf \large {\sqrt{x^3y^2}\sqrt[4]{xy^3}\implies \sqrt{x^3y^2} \cdot \sqrt[4]{xy^3}\\ \textit{keeping in mind that } a^{\frac{n}{m}} = \sqrt[m]{a^n}\\ \left(x^3y^2\right)^{\frac{1}{2}} \cdot \left(xy^3\right)^{\frac{1}{4}} \implies x^{\frac{1}{6}} y^{\frac{1}{4}}x^{\frac{1}{4}}y^{\frac{1}{12}} \implies x^{\frac{1}{6}+\frac{1}{4}} y^{\frac{1}{4}+\frac{1}{12}}}\)
anonymous
  • anonymous
\(\left(x^3y^2\right)^{\frac{1}{2}} \cdot \left(xy^3\right)^{\frac{1}{4}} \) \(x^{3\cdot \frac{1}{2}}=x^{\frac{3}{2}}\) \(y^{2\cdot \frac{1}{2}}=y^{\frac{2}{2}}=y\) So your first term is: \(x^{\frac{3}{2}}y\)

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