A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmm, technically, the inverse is just swapping about the variables, now the simplification, well, not so simplistic

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0exactly, I know the concept it's just that I have to show my work to simplify and insert a value into the new function.

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.1Interesting... Can somebody find the inverse function for \(y=x^2+2x3\) ?

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2yes... but you will have to restrict the domain.

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.1Two branches will satisfy: \[1\pm\sqrt{4+x}.\]Now how to solve this one? \[2y^5+y^3+1x=0.\]

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0throwing it into wolframalpha gives this result http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ef49hilhcgk

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.1This means that the inverse function may not be found.

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0whaaaaaat...... But It's in my textbook and part of my homework! Ugh...

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2what are you studying?

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0calc one... this is the second day of homework.

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2you sure it's a 5th power?

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0sorry, that's the class. I'm studying Electrical Engineering. just a second and I'll upload a snapshot of the problem

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2dude... it says f^1(a) and gives you the value of a. inverse functions work like this... plug in the y from a function into its inverse and you get out x. compute f(a) for your functions and then f^1(f(a)) will just be a.

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0I know, and I have the 71 as the answer, but it also asks to write down the function which I can't find to save my life!

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2oops... i misread. but i doesn't ask for the inverse function... only f^1(a)

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0OH! oh oh oh oh.... Damn....

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2if you find a = f(x) then the x that satisfies this will be f^1(a)

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.0Wow that's a lot easier than finding \(f^{1}(x)\) :)

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0craaaaap.... well there went an hour I'll never get back. thanks for all your help guys

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2no worries... maybe post the question from your book and your interpretation so you can get to the heart of the sunrise quicker.

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.1So, what is an answer?

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2x = 1 2 = 2x^5 + x^3 +1 => 2x^5 + x^3 +3 = 0 the only real solution is x = 1

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0yeah I get what you mean now... but isn't that just f(2) now? not the inverse?

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2no... f(1) = 2 so f^1(2) = 1

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.0Remember that \(f^{1}(2)\) is that domain element x that gives you \(f(x)=2\) The function maps the domain to the range. The inverse function maps the range back to the domain.

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.1Let \(f^{1}(a)=x\). Now map \(f\) to both of the parts of the equation and use \(f(f^{1}(a))=a\). It will become\[a=f(x)\]Solve this and you will obtain an answer.

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.0So by setting \(f(x)=y=2\) and solving, you find the x in the domain that takes you to y in the range.

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0ohhh okay, so put the variable as the solution and work backwards

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2they give you a = f(x) and want you to find f^1(a) = f^1(f(x)) = x so setting f(x) = a and solving for x gives you what you need.

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0Yep :) thanks again y'all

TimmyG
 one year ago
Best ResponseYou've already chosen the best response.0*lightbulb turns on* I think the rest of this will be much easier now

pgpilot326
 one year ago
Best ResponseYou've already chosen the best response.2awesome! let's turn the dark into light!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.