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anonymous
 3 years ago
I need help with finding the inverse of this function, 2x^5+x^3+1.
anonymous
 3 years ago
I need help with finding the inverse of this function, 2x^5+x^3+1.

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jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0hmm, technically, the inverse is just swapping about the variables, now the simplification, well, not so simplistic

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0exactly, I know the concept it's just that I have to show my work to simplify and insert a value into the new function.

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1Interesting... Can somebody find the inverse function for \(y=x^2+2x3\) ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes... but you will have to restrict the domain.

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1Two branches will satisfy: \[1\pm\sqrt{4+x}.\]Now how to solve this one? \[2y^5+y^3+1x=0.\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0throwing it into wolframalpha gives this result http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ef49hilhcgk

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1This means that the inverse function may not be found.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0whaaaaaat...... But It's in my textbook and part of my homework! Ugh...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what are you studying?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0calc one... this is the second day of homework.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you sure it's a 5th power?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry, that's the class. I'm studying Electrical Engineering. just a second and I'll upload a snapshot of the problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dude... it says f^1(a) and gives you the value of a. inverse functions work like this... plug in the y from a function into its inverse and you get out x. compute f(a) for your functions and then f^1(f(a)) will just be a.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know, and I have the 71 as the answer, but it also asks to write down the function which I can't find to save my life!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oops... i misread. but i doesn't ask for the inverse function... only f^1(a)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OH! oh oh oh oh.... Damn....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you find a = f(x) then the x that satisfies this will be f^1(a)

DebbieG
 3 years ago
Best ResponseYou've already chosen the best response.0Wow that's a lot easier than finding \(f^{1}(x)\) :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0craaaaap.... well there went an hour I'll never get back. thanks for all your help guys

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no worries... maybe post the question from your book and your interpretation so you can get to the heart of the sunrise quicker.

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1So, what is an answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x = 1 2 = 2x^5 + x^3 +1 => 2x^5 + x^3 +3 = 0 the only real solution is x = 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah I get what you mean now... but isn't that just f(2) now? not the inverse?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no... f(1) = 2 so f^1(2) = 1

DebbieG
 3 years ago
Best ResponseYou've already chosen the best response.0Remember that \(f^{1}(2)\) is that domain element x that gives you \(f(x)=2\) The function maps the domain to the range. The inverse function maps the range back to the domain.

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.1Let \(f^{1}(a)=x\). Now map \(f\) to both of the parts of the equation and use \(f(f^{1}(a))=a\). It will become\[a=f(x)\]Solve this and you will obtain an answer.

DebbieG
 3 years ago
Best ResponseYou've already chosen the best response.0So by setting \(f(x)=y=2\) and solving, you find the x in the domain that takes you to y in the range.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh okay, so put the variable as the solution and work backwards

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0they give you a = f(x) and want you to find f^1(a) = f^1(f(x)) = x so setting f(x) = a and solving for x gives you what you need.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yep :) thanks again y'all

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0*lightbulb turns on* I think the rest of this will be much easier now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0awesome! let's turn the dark into light!
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