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\[2x^5+x^3+1\]

Interesting...
Can somebody find the inverse function for \(y=x^2+2x-3\) ?

yes... but you will have to restrict the domain.

Two branches will satisfy:
\[-1\pm\sqrt{4+x}.\]Now how to solve this one?
\[2y^5+y^3+1-x=0.\]

This means that the inverse function may not be found.

whaaaaaat...... But It's in my textbook and part of my homework! Ugh...

what are you studying?

calc one... this is the second day of homework.

you sure it's a 5th power?

#74

Hahaha. Lol.

hmm well well

oops... i misread. but i doesn't ask for the inverse function... only f^-1(a)

OH! oh oh oh oh.... Damn....

if you find a = f(x) then the x that satisfies this will be f^-1(a)

Wow that's a lot easier than finding \(f^{-1}(x)\) :)

yeah, it's -71...

craaaaap.... well there went an hour I'll never get back. thanks for all your help guys

So, what is an answer?

it's not -71

no?

x = -1
-2 = 2x^5 + x^3 +1 => 2x^5 + x^3 +3 = 0
the only real solution is x = -1

yeah I get what you mean now... but isn't that just f(-2) now? not the inverse?

no... f(-1) = -2 so
f^-1(-2) = -1

f^-1(f(x)) = x

ohhh okay, so put the variable as the solution and work backwards

make sense?

Yep :) thanks again y'all

you're welcome!

*lightbulb turns on* I think the rest of this will be much easier now

awesome! let's turn the dark into light!