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TimmyG
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I need help with finding the inverse of this function, 2x^5+x^3+1.
 11 months ago
 11 months ago
TimmyG Group Title
I need help with finding the inverse of this function, 2x^5+x^3+1.
 11 months ago
 11 months ago

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TimmyG Group TitleBest ResponseYou've already chosen the best response.0
\[2x^5+x^3+1\]
 11 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
hmm, technically, the inverse is just swapping about the variables, now the simplification, well, not so simplistic
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
exactly, I know the concept it's just that I have to show my work to simplify and insert a value into the new function.
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Interesting... Can somebody find the inverse function for \(y=x^2+2x3\) ?
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
yes... but you will have to restrict the domain.
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Two branches will satisfy: \[1\pm\sqrt{4+x}.\]Now how to solve this one? \[2y^5+y^3+1x=0.\]
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
throwing it into wolframalpha gives this result http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ef49hilhcgk
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
This means that the inverse function may not be found.
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
whaaaaaat...... But It's in my textbook and part of my homework! Ugh...
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
what are you studying?
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
calc one... this is the second day of homework.
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
you sure it's a 5th power?
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
sorry, that's the class. I'm studying Electrical Engineering. just a second and I'll upload a snapshot of the problem
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Hahaha. Lol.
 11 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
hmm well well
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
dude... it says f^1(a) and gives you the value of a. inverse functions work like this... plug in the y from a function into its inverse and you get out x. compute f(a) for your functions and then f^1(f(a)) will just be a.
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
I know, and I have the 71 as the answer, but it also asks to write down the function which I can't find to save my life!
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
oops... i misread. but i doesn't ask for the inverse function... only f^1(a)
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
OH! oh oh oh oh.... Damn....
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
if you find a = f(x) then the x that satisfies this will be f^1(a)
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
Wow that's a lot easier than finding \(f^{1}(x)\) :)
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
yeah, it's 71...
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
craaaaap.... well there went an hour I'll never get back. thanks for all your help guys
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
no worries... maybe post the question from your book and your interpretation so you can get to the heart of the sunrise quicker.
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
So, what is an answer?
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
it's not 71
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
x = 1 2 = 2x^5 + x^3 +1 => 2x^5 + x^3 +3 = 0 the only real solution is x = 1
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
yeah I get what you mean now... but isn't that just f(2) now? not the inverse?
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
no... f(1) = 2 so f^1(2) = 1
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
Remember that \(f^{1}(2)\) is that domain element x that gives you \(f(x)=2\) The function maps the domain to the range. The inverse function maps the range back to the domain.
 11 months ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Let \(f^{1}(a)=x\). Now map \(f\) to both of the parts of the equation and use \(f(f^{1}(a))=a\). It will become\[a=f(x)\]Solve this and you will obtain an answer.
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
So by setting \(f(x)=y=2\) and solving, you find the x in the domain that takes you to y in the range.
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
f^1(f(x)) = x
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
ohhh okay, so put the variable as the solution and work backwards
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
they give you a = f(x) and want you to find f^1(a) = f^1(f(x)) = x so setting f(x) = a and solving for x gives you what you need.
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
make sense?
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
Yep :) thanks again y'all
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
you're welcome!
 11 months ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
*lightbulb turns on* I think the rest of this will be much easier now
 11 months ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
awesome! let's turn the dark into light!
 11 months ago
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