Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
TimmyG
Group Title
I need help with finding the inverse of this function, 2x^5+x^3+1.
 one year ago
 one year ago
TimmyG Group Title
I need help with finding the inverse of this function, 2x^5+x^3+1.
 one year ago
 one year ago

This Question is Closed

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
\[2x^5+x^3+1\]
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
hmm, technically, the inverse is just swapping about the variables, now the simplification, well, not so simplistic
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
exactly, I know the concept it's just that I have to show my work to simplify and insert a value into the new function.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Interesting... Can somebody find the inverse function for \(y=x^2+2x3\) ?
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
yes... but you will have to restrict the domain.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Two branches will satisfy: \[1\pm\sqrt{4+x}.\]Now how to solve this one? \[2y^5+y^3+1x=0.\]
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
throwing it into wolframalpha gives this result http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427ef49hilhcgk
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
This means that the inverse function may not be found.
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
whaaaaaat...... But It's in my textbook and part of my homework! Ugh...
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
what are you studying?
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
calc one... this is the second day of homework.
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
you sure it's a 5th power?
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
sorry, that's the class. I'm studying Electrical Engineering. just a second and I'll upload a snapshot of the problem
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Hahaha. Lol.
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
hmm well well
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
dude... it says f^1(a) and gives you the value of a. inverse functions work like this... plug in the y from a function into its inverse and you get out x. compute f(a) for your functions and then f^1(f(a)) will just be a.
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
I know, and I have the 71 as the answer, but it also asks to write down the function which I can't find to save my life!
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
oops... i misread. but i doesn't ask for the inverse function... only f^1(a)
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
OH! oh oh oh oh.... Damn....
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
if you find a = f(x) then the x that satisfies this will be f^1(a)
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
Wow that's a lot easier than finding \(f^{1}(x)\) :)
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
yeah, it's 71...
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
craaaaap.... well there went an hour I'll never get back. thanks for all your help guys
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
no worries... maybe post the question from your book and your interpretation so you can get to the heart of the sunrise quicker.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
So, what is an answer?
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
it's not 71
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
x = 1 2 = 2x^5 + x^3 +1 => 2x^5 + x^3 +3 = 0 the only real solution is x = 1
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
yeah I get what you mean now... but isn't that just f(2) now? not the inverse?
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
no... f(1) = 2 so f^1(2) = 1
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
Remember that \(f^{1}(2)\) is that domain element x that gives you \(f(x)=2\) The function maps the domain to the range. The inverse function maps the range back to the domain.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
Let \(f^{1}(a)=x\). Now map \(f\) to both of the parts of the equation and use \(f(f^{1}(a))=a\). It will become\[a=f(x)\]Solve this and you will obtain an answer.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
So by setting \(f(x)=y=2\) and solving, you find the x in the domain that takes you to y in the range.
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
f^1(f(x)) = x
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
ohhh okay, so put the variable as the solution and work backwards
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
they give you a = f(x) and want you to find f^1(a) = f^1(f(x)) = x so setting f(x) = a and solving for x gives you what you need.
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
make sense?
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
Yep :) thanks again y'all
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
you're welcome!
 one year ago

TimmyG Group TitleBest ResponseYou've already chosen the best response.0
*lightbulb turns on* I think the rest of this will be much easier now
 one year ago

pgpilot326 Group TitleBest ResponseYou've already chosen the best response.2
awesome! let's turn the dark into light!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.