anonymous
  • anonymous
Could someone show me how to simplify (5m - 2) - (3m - 2n + 5)?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ivettef365
  • ivettef365
first take out parenthesis as follows: 5m-2-3m+2n-5 now combine like terms
anonymous
  • anonymous
Ivette is right :)
anonymous
  • anonymous
Omg! My mistake it's -2 -5 = -7!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So the correct answer is 2m + 2n -7 I'm so sorry!
anonymous
  • anonymous
Thank you all!
anonymous
  • anonymous
You're welcome! :)
anonymous
  • anonymous
You've all been such a big help.
anonymous
  • anonymous
I'm glad I helped :)
anonymous
  • anonymous
Could someone help me with one more?
anonymous
  • anonymous
Sure, post it!
anonymous
  • anonymous
Okay, simplify: \[(16x ^{4} - 4x ^{3} + 8x - 7) - (5x ^{4} + 4x ^{2} - 8x +12)\]
anonymous
  • anonymous
you have to distribute that - to the 5 4 -8 and 12
anonymous
  • anonymous
11x^4 - 8x^3 + 16 x - 19
anonymous
  • anonymous
It's all adding and subtracting to the like terms! Really easy!
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
You are welcome!
anonymous
  • anonymous
The way i think about adding like terms is like normal addint 123+341 123 + 341 464 ----------- as you can see we have hundred, tens and ones. We cant add the tens to the ones or hundreds to tens... you get the idea. They have to be same. In algebra you have powers 1x^2+2x+3 + 3x^2+4x+1 1x^2+2x+3 +3x^2+4x+1 4x^2+6x+4 I see them as x^2s, xs and constants the one without an x :). It is like you would see hundreds, tens, and ones Also when you do it with algebraic like terms there is no carrying over it just stands as is. Example: 19 +12 31 vs alebra 9x +2x 11x no carry over

Looking for something else?

Not the answer you are looking for? Search for more explanations.