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If A is an n x n matrix function such that A and \(\frac{dA}{dt}\)are the same function, then A = c\(e^tI_n\)for some constant c.
True or false? why?
Please, help
 7 months ago
 7 months ago
If A is an n x n matrix function such that A and \(\frac{dA}{dt}\)are the same function, then A = c\(e^tI_n\)for some constant c. True or false? why? Please, help
 7 months ago
 7 months ago

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klimenkovBest ResponseYou've already chosen the best response.1
If \(A=\left(\begin{matrix}e^{t} & 2e^{t} \\ 3e^{t}& 4e^{x}\end{matrix}\right)\), what is \(\frac{dA}{dt}\)?
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
\[\frac{dA}{dt}=A ~~but~~A\neq ce^tI_n\]therefore, it's false, right?
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
the area of ACDE = area ABE + area BCDE = AB *EB/2 + EB*BC = 4*4\(\frac{\sqrt{3}}{2}\)+4\(\sqrt{3}\)*11
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
since AB=4 , BC=11. got it? it is = 8\(\sqrt{3}\)+44\(\sqrt{3}\)=52\(\sqrt{3}\)
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
@MayMay_69 that's yours. Take it, I am gonna delete it.
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
@oldrin.bataku am I right for my own problem?
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
I am sorry for messing up. May may asked for help but he/she has no link, I used my post to anser him/her
 7 months ago

oldrin.batakuBest ResponseYou've already chosen the best response.1
@Loser66 @klimenkov gave a counterexample :p
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
that means the answer is "False" right?
 7 months ago

oldrin.batakuBest ResponseYou've already chosen the best response.1
it need not be \(A=ce^tI_n\) merely \(A=e^tB\) for constant matrix \(B\)
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
thank you very much. @oldrin.bataku
 7 months ago

MayMay_69Best ResponseYou've already chosen the best response.0
okay thank you very very much loser
 7 months ago

Loser66Best ResponseYou've already chosen the best response.2
You got what I mean, right? @MayMay_69
 7 months ago
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