anonymous
  • anonymous
if x^2 > 0, then x < 0. Is that statement true or false?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ivettef365
  • ivettef365
what do you think ?
anonymous
  • anonymous
x>0 or x<0
anonymous
  • anonymous
x<0

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More answers

DebbieG
  • DebbieG
Can you find a counterexample?
anonymous
  • anonymous
-1
DebbieG
  • DebbieG
It says if x^2 > 0, then x < 0. So if you can find an x>0 such that if x^2 > 0, then that DISproves it, hence it is false.
anonymous
  • anonymous
oh wait. nevermind -1*-1 = 1
anonymous
  • anonymous
-1 fits the definition... what about something that works in the first part but not the second?
DebbieG
  • DebbieG
Note, however, that the reverse is not true: finding an example for which the statement is true does not PROVE that it's true IN GENERAL. But finding an example that proves IT'S FALSE does prove that it's NOT TRUE in genera.
anonymous
  • anonymous
2
DebbieG
  • DebbieG
So what does that tell you? is it true or false?
anonymous
  • anonymous
Pretty sure it's false. be> 0, or 4 >0, then 4 < 0???
anonymous
  • anonymous
because 2^2 > 0
DebbieG
  • DebbieG
Exactly. :)
radar
  • radar
What if x has a complex value like 2i ?
anonymous
  • anonymous
WOOOT THANKS DEBBIE
radar
  • radar
x = -2, x^2 =4 x =2 , x^2 =4 x=2i, x^2=-4
anonymous
  • anonymous
just no.
anonymous
  • anonymous
but which is greater? 2i or -2i? also, is either of these greater or less than 0?
anonymous
  • anonymous
greater
anonymous
  • anonymous
can't compare complex numbers... only their moduli!
anonymous
  • anonymous
so?..
radar
  • radar
@pgpilot326 Equal but opposite. and when both are squared (-2i)^2 or (2i)^2 the result is still -4 which is less than zero. The drawing shows their relationship to zero, I will let you decide which one is less than or greater than zero :) l|dw:1377641500857:dw|
anonymous
  • anonymous
1+i or 1 - i?
anonymous
  • anonymous
besides is 2i >0? if so, is -2i>0? can both be?
anonymous
  • anonymous
not really?

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