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anonymous
 3 years ago
Help!
Simplify:
1. (z)^3(3z^4)
2. 5(x^2z^6)^3(5x^2z^6)^3
Thank you!:)
anonymous
 3 years ago
Help! Simplify: 1. (z)^3(3z^4) 2. 5(x^2z^6)^3(5x^2z^6)^3 Thank you!:)

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jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2what does (z)^3 simplify to

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0z? I don't know... :/

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2(z)^3 = (1*z)^3 (z)^3 = (1)^3*(z)^3 (z)^3 = 1*z^3 (z)^3 = z^3

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2(z)^3(3z^4) turns into z^3*3z^4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0add the z's but the negative is still messing me up :/

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2think of z^3*3z^4 as 1z^3*3z^4

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2so the coefficients are 1 and 3, they multiply to 1*3 = 3

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2z^3 times z^4 = z^(3+4) = z^7 so the final answer is 3z^7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you! :) can you help me with the second one as well?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2how far did you get with it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does exponents distribute first? if so, does the ^3 distribute to the 5 as well or just the (x^2z^6)?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2the exponent of 3 only applies to terms inside the parenthesis

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2so (x^2z^6)^3 means you cube x^2 and z^6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got 1/25 after simplifying

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2you are correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you for helping me! :) you're the best! :)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2you're welcome
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