Graph the linear equation by solving For y first
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then substitute X to -1, 1, 2, 3
whatever you get Y and the numbers you substituted to X plot a graph
2x + 3y = 3
3y = -2x + 3
y = -2/3x + 1
put a circle on the y line at 1. The slope is -2/3, so from the 1 on the y line, come down 2, and to the right 3, then down 2 and to the right 3.
The x intercept is : 2x + 3y = 3.....2x + 3(0) = 3....2x = 3....x = 3/2 or 1 1/2. This is where the line crosses the x axis. It crosses the y axis at 1.
i marked it wrong so i got it wrong i was off by a smudge
i have a new one ugh i hate graphing
to find the x intercept, sub 0 in for y
to find the y intercept, sub in 0 for x
to find the slope, put your equation in y = mx + b where m is your slope
x + 5y = 15
5y = -x + 15
y = -1/5 + 3
3 is your y intercept.
slope is -1/5....so from the 3 on your y intercept, come down 1(because it is negative) and to the right 5 (because it is positive)
Your line should cross the x axis at :
x + 5y = 15
x + 5(0) = 15
x = 15
it should cross the x axis at 15, and the y axis at 3
or just go here....punch in graphing calculator....on the first line, write your equation, and go to the bottom and click graph...