anonymous
  • anonymous
How many units apart are the points (4, -3) and (-4, 3)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Can someone please explain?
DebbieG
  • DebbieG
Use the distance formula to find the distance between two points: \[d=\sqrt{(X_{1}-X_{2})^{2}+(Y_{1}-Y_{2})^{2}}\] Just plug in your point coordinates and simplify.
anonymous
  • anonymous
so 4-(-4) ^+ (-3)-3^ ????????? then do the square root of what I get?

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DebbieG
  • DebbieG
You need to square each of those differences (I think that's what you mean, but it's hard to tell with just text).
DebbieG
  • DebbieG
Tell me what you get, and I'll tell you if it's right. :)
anonymous
  • anonymous
Would it be 64+9=73 then I square root 73?
DebbieG
  • DebbieG
Check that 9.
DebbieG
  • DebbieG
\((-3-3)^2=?\)
anonymous
  • anonymous
um...0 ?
DebbieG
  • DebbieG
What's -3-3?
anonymous
  • anonymous
-3 - 3 = -6
anonymous
  • anonymous
so 58 ?
DebbieG
  • DebbieG
Good. now square that...? And add to 64
DebbieG
  • DebbieG
No, look at the equation again. You squared the difference of x's but are forgetting to square the difference of the y's. :)
anonymous
  • anonymous
oh so that means I have to square 64 then too right?
DebbieG
  • DebbieG
No, the 64 is already the square!
anonymous
  • anonymous
OH I GET WHAT U MEAN
anonymous
  • anonymous
I was getting confused with the square root ,and squared
DebbieG
  • DebbieG
Just take it one step at at time. :)
anonymous
  • anonymous
3364 ?
DebbieG
  • DebbieG
Oh lord. how did you get that? lol
anonymous
  • anonymous
58x58 i dunno!
anonymous
  • anonymous
what do I do!!?!?
DebbieG
  • DebbieG
sorry, i'm having technical issues.... hang on.
anonymous
  • anonymous
Oh okay (:
DebbieG
  • DebbieG
\[d=\sqrt{(-4-4)^{2}+(3-(-3))^2}\] \[=\sqrt{(-8)^{2}+(6)^2}\] You basically got this far (notice I changed the order, just to be consistent with the formula in terms of calling the the point "1" and the other point "2"... but the order you subtract the coordinates in won't really matter, since it only changes the sign and we are going to square the result).
DebbieG
  • DebbieG
NOW do the squares FIRST - they are under the square root - so you need \[(-8)^{2} ~~\text{and}~~~ 6^2\]
anonymous
  • anonymous
-64 ? and 36?
DebbieG
  • DebbieG
No real number, squared, is negative
DebbieG
  • DebbieG
(but the 36 is correct)
anonymous
  • anonymous
so its just left as 64 and 36
DebbieG
  • DebbieG
remember, it's \((-8)^2\), NOT \(-8^2\), there is an important difference!
DebbieG
  • DebbieG
Well, yes, it's "left" as those because that's what they ARE! :) OK, so now you have: \[\Large =\sqrt{64+36}\] Do the sum. THEN take the root.
anonymous
  • anonymous
64+36=100 then rooted=10
DebbieG
  • DebbieG
Tah-dah! :)
anonymous
  • anonymous
So thats my answer? 10 Units away?
DebbieG
  • DebbieG
yeppers, that's what the distance formula tells you. :)
anonymous
  • anonymous
wow thanks (: explained very well...I dunno how to give you more than 1 medal id give you like 5 or something if I could
DebbieG
  • DebbieG
Haha, thanks, one is fine. :) Happy to have helped, good job sticking with it and working through the explanation! :)

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