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you know the word x-intercept means it is where the line hits the x-axis and that's only possible if the value of y is zero. So why don't you go ahead and solve the equation when the value of y is zero.
@RaWr12321 coocoobird, are you paying attention or you're just going to wait for an answer?
watching what? that's all what x-intercept means - the value of y is zero. SOLVE it, coocoo
But you see, I know the answer is 2 plus or minus rad 2 over 2... but when i tried to get to it, i got 1 plus or minus rad 2 over 2..
the graph I showed you is just a general demonstration of what an x-intercept meant.
i know what x-intercept means. i just want to know where my mistake was
oh okay. show me your solution then
According to the book, i first needed to complete the square so I did, and I got y=4(x-1)^2-2 (which is right because the vertex was correct in the book), then as you said i put in 0 for y.. so its 0=4(x-1)^2-2.. but once i solve that. it turns out to be 1 plus or minus rad 2 over 2
Reverse the equality in 0 = 4 x^2-8 x+2 in order to isolate x to the left hand side. 0 = 4 x^2-8 x+2 is equivalent to 4 x^2-8 x+2 = 0: 4 x^2-8 x+2 = 0 Write the quadratic equation in standard form. Divide both sides by 4: x^2-2 x+1/2 = 0 Solve the quadratic equation by completing the square. Subtract 1/2 from both sides: x^2-2 x = -1/2 Take one half of the coefficient of x and square it, then add it to both sides. Add 1 to both sides: x^2-2 x+1 = 1/2 Factor the left hand side. Write the left hand side as a square: (x-1)^2 = 1/2 Eliminate the exponent on the left hand side. Take the square root of both sides: x-1 = 1/sqrt(2) or x-1 = -1/sqrt(2) Look at the first equation: Solve for x. Add 1 to both sides: x = 1+1/sqrt(2) or x-1 = -1/sqrt(2) Look at the second equation: Solve for x. Add 1 to both sides: Answer: x = 1+1/sqrt(2) or x = 1-1/sqrt(2)
are you still lost, coocoobird?
@rawr12321 are you escaping from your responsibilities?