anonymous
  • anonymous
How do I do the Pythagorean Theorem for this? 13 square root 5 + b^2 = 13^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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nincompoop
  • nincompoop
why do you want to use the Pythagorean Theorem?
anonymous
  • anonymous
Trig Function.
nincompoop
  • nincompoop
? okay… and?

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anonymous
  • anonymous
It says find sec θ if sin θ = 3 square root 13 / 13
anonymous
  • anonymous
I need to label the triangle of the missing adjacent side.
nincompoop
  • nincompoop
do it.
anonymous
  • anonymous
I don't know how to do a^2 with the 3 square root 13..
nincompoop
  • nincompoop
you don't know what?
nincompoop
  • nincompoop
you mean cube root?
anonymous
  • anonymous
\[3\sqrt{13}\]
nincompoop
  • nincompoop
that means \[\sqrt{13\times9}\]
anonymous
  • anonymous
\[\sqrt{117}\]
nincompoop
  • nincompoop
k what do you do next?
nincompoop
  • nincompoop
are you trying to solve b in 13 square root 5 + b^2 = 13^2 ?
anonymous
  • anonymous
So \[\sqrt{117}+ b^2 = 169\]
anonymous
  • anonymous
How do I continue off of that?
nincompoop
  • nincompoop
you might want to isolate b^2 by deducting the whole sqrt(117) on both sides
anonymous
  • anonymous
Would it just be 169 - \[\sqrt{117}\] on the c side?
nincompoop
  • nincompoop
I don't think your equation was written out properly, but we'll see
Luigi0210
  • Luigi0210
Pfft, you don't need me, you got the great Nin here
anonymous
  • anonymous
Sorry I thought he wasn't reading anymore!
nincompoop
  • nincompoop
what c side? now try to get rid of the exponent 2 by obtaining the square root of b^2 and also of the other side of the equation
anonymous
  • anonymous
\[b^2 = 169 - \sqrt{117}\]
anonymous
  • anonymous
Is what I'm understanding.
nincompoop
  • nincompoop
just about right
nincompoop
  • nincompoop
if you want to solve for b, you isolate it to one side
anonymous
  • anonymous
It is isolated.
nincompoop
  • nincompoop
we accomplished that
nincompoop
  • nincompoop
but you have b^2 still a square root of b^2 is b so try to square root both sides of the equation
anonymous
  • anonymous
b = \[\sqrt{169-\sqrt{117}}\]
nincompoop
  • nincompoop
ya square root of 169 is?
anonymous
  • anonymous
13.
nincompoop
  • nincompoop
great! now square root of a square root means?
anonymous
  • anonymous
I'm not sure..
nincompoop
  • nincompoop
it's the same as exponents, you multiply the radical
anonymous
  • anonymous
So how does that look?
nincompoop
  • nincompoop
|dw:1377655376103:dw|
anonymous
  • anonymous
Still confused. Can you finish it off for me so I can study what you did?
nincompoop
  • nincompoop
no.
nincompoop
  • nincompoop
root of a root means you multiply the roots. it's like a power of a power in exponents (a^2)^2 = a^(2x2) = a^4
anonymous
  • anonymous
Well I'm not understanding.. and this is needlessly time consuming.
nincompoop
  • nincompoop
that's what math is… everyone has to go through this. you won't understand why I did what I did if you'r just reading off my solutions.
anonymous
  • anonymous
I'll just ask for help in class but thanks anyways.
nincompoop
  • nincompoop
okay

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