anonymous
  • anonymous
Show that e^x grows faster than e^cos(x).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Show that \(\dfrac{d}{dx}e^x>\dfrac{d}{dx}e^{\cos x}\).
anonymous
  • anonymous
You'll probably have to use the fact that \(\cos x\) and \(\sin x\) are bounded by \(\pm1\).
anonymous
  • anonymous
Sorry, I don't understand what you wrote.

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anonymous
  • anonymous
Show that the derivative (rate of change) of e^x is greater than the derivative of e^(cos x).
anonymous
  • anonymous
Latex problems again?
anonymous
  • anonymous
Do you have to take the limit?
anonymous
  • anonymous
Yes, I think the question will have you consider the end behavior of e^x and -sinx e^(cosx). |dw:1377656470348:dw|
anonymous
  • anonymous
As x gets large, e^x approaches infinity. On the right side, -sinx and cosx are bounded between -1 and 1, so you effectively have e^∞ > -(±1) e^(±1) ∞ > ± e^(±1)

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