anonymous
  • anonymous
3(3x-1)^2=21 solve the equation algebraically
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
This is actually 3(3x -1)(3x-1) = 21 All you need to do is expand the brackets then simplify.
anonymous
  • anonymous
x = 1.21525043702153
anonymous
  • anonymous
Make sure you then shift the 21 so the right side equating the equation to 0 to solve.

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anonymous
  • anonymous
Can you do the rest?
anonymous
  • anonymous
my answer sheet said that the correct answer ia \[\sqrt{7}/3 \pm1/3\]
anonymous
  • anonymous
you can start be dividing both sides of the equation by 3 this will give you a new equations (3x-1)^2 = 7 then square root both sides 3x-1 = 7^(1/2) [or root 7] and 1 to both sides the divide by 3 gives you: x= ((sqr.root 7) + 1)/3 which is x = 1.21525043702153
anonymous
  • anonymous
oh ok'

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