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OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
http://www.webmath.com/nintegrate.html Best website that gives you step by step instructions!
 11 months ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.0
\[\int_{\frac{1}{3}}^{1}\frac{\sqrt[3]{xx^3}}{x^4}dx\]?
 11 months ago

shayanreloaded Group TitleBest ResponseYou've already chosen the best response.0
yes
 11 months ago

cinar Group TitleBest ResponseYou've already chosen the best response.1
\[ \Large \int_{\frac{1}{3}}^{1}\frac{\sqrt[3]{xx^3}}{x^4}dx\\ \Large \int_{\frac{1}{3}}^{1}\frac{\sqrt[3]{x^3(\frac{1}{x^2}1)}}{x^4}dx\\ \Large \int_{\frac{1}{3}}^{1}\frac{x\sqrt[3]{\frac{1}{x^2}1}}{x^4}dx\\ \Large \int_{\frac{1}{3}}^{1}\frac{\sqrt[3]{\frac{1}{x^2}1}}{x^3}dx\\ \Large u=\frac{1}{x^2}=>du=\frac{2}{x^3}dx\\ \Large \frac{1}{2}\int\sqrt[3]{u1}du\\ \]the reset is yours (: you can do one more subt.
 11 months ago

cinar Group TitleBest ResponseYou've already chosen the best response.1
I guess this subt. is better\[ \Large u=\frac{1}{x^2}1=>du=\frac{2}{x^3}dx\\ \Large \frac{1}{2}\int\sqrt[3]{u}du\\ \Large \frac{1}{2}\frac{3}{4}u^{\frac{4}{3}}\\ \Large \frac{3}{8}(\frac{1}{x^2}1)^{\frac{4}{3}}_{\frac{1}3}^{1}=6\\ \]
 11 months ago
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