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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2It's the same as: \[\sqrt[2]{4^3}\]

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.0What is \(\sqrt 4\) ?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Yes, now what's \[\sqrt{64}\]

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2@klimenkov 's method would of worked too

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2And that's your answer

izhangy
 one year ago
Best ResponseYou've already chosen the best response.0alrighty what is 8^(2/3)?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2and what's \[\sqrt[3]{64}\]

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.0I think i would be easier to compute \(8^{\frac13}\) first.

izhangy
 one year ago
Best ResponseYou've already chosen the best response.0ohh dood 1 more please

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Is that 1/2 with the whole equation or just 2?

izhangy
 one year ago
Best ResponseYou've already chosen the best response.0sq root 8 divided by 2 to the half power

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Well the 1/2 makes that 2 a rad 2: \[\frac{\sqrt{8}}{\sqrt{2}}\] Now what does \[\sqrt{8}\] simplify into?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Yup! \[\frac{2\sqrt{2}}{\sqrt{2}}\] Can you finish it?

izhangy
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to calculate average rate of change?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Anytime. Average rate of change? As in calculus?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Sorry, I haven't had calculus for a while :/ just open a new question and call Nincompoop, he's great at calculus

izhangy
 one year ago
Best ResponseYou've already chosen the best response.0ah alrighty thanks dood.

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2Yup, and if he's not on call dan815
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