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izhangy
 2 years ago
what is 4^(3/2)? How do you show work for it?
izhangy
 2 years ago
what is 4^(3/2)? How do you show work for it?

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Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2It's the same as: \[\sqrt[2]{4^3}\]

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.0What is \(\sqrt 4\) ?

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Yes, now what's \[\sqrt{64}\]

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2@klimenkov 's method would of worked too

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2And that's your answer

izhangy
 2 years ago
Best ResponseYou've already chosen the best response.0alrighty what is 8^(2/3)?

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2and what's \[\sqrt[3]{64}\]

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.0I think i would be easier to compute \(8^{\frac13}\) first.

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Is that 1/2 with the whole equation or just 2?

izhangy
 2 years ago
Best ResponseYou've already chosen the best response.0sq root 8 divided by 2 to the half power

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Well the 1/2 makes that 2 a rad 2: \[\frac{\sqrt{8}}{\sqrt{2}}\] Now what does \[\sqrt{8}\] simplify into?

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Yup! \[\frac{2\sqrt{2}}{\sqrt{2}}\] Can you finish it?

izhangy
 2 years ago
Best ResponseYou've already chosen the best response.0do you know how to calculate average rate of change?

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Anytime. Average rate of change? As in calculus?

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Sorry, I haven't had calculus for a while :/ just open a new question and call Nincompoop, he's great at calculus

izhangy
 2 years ago
Best ResponseYou've already chosen the best response.0ah alrighty thanks dood.

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.2Yup, and if he's not on call dan815
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