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izhangy

what is 4^(3/2)? How do you show work for it?

  • 7 months ago
  • 7 months ago

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  1. Luigi0210
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    It's the same as: \[\sqrt[2]{4^3}\]

    • 7 months ago
  2. Luigi0210
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    What's 4^3?

    • 7 months ago
  3. izhangy
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    oh alright, 4^3=64...

    • 7 months ago
  4. klimenkov
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    What is \(\sqrt 4\) ?

    • 7 months ago
  5. Luigi0210
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    Yes, now what's \[\sqrt{64}\]

    • 7 months ago
  6. Luigi0210
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    @klimenkov 's method would of worked too

    • 7 months ago
  7. izhangy
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    8

    • 7 months ago
  8. Luigi0210
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    And that's your answer

    • 7 months ago
  9. izhangy
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    alrighty what is 8^(2/3)?

    • 7 months ago
  10. Luigi0210
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    what's 8^2?

    • 7 months ago
  11. izhangy
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    64

    • 7 months ago
  12. Luigi0210
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    and what's \[\sqrt[3]{64}\]

    • 7 months ago
  13. izhangy
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    ohhhh 4

    • 7 months ago
  14. Luigi0210
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    Yup!

    • 7 months ago
  15. izhangy
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    thanks dood

    • 7 months ago
  16. klimenkov
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    I think i would be easier to compute \(8^{\frac13}\) first.

    • 7 months ago
  17. izhangy
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    ohh dood 1 more please

    • 7 months ago
  18. izhangy
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    what is √(8)/2^(1/2)?

    • 7 months ago
  19. Luigi0210
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    Is that 1/2 with the whole equation or just 2?

    • 7 months ago
  20. izhangy
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    sq root 8 divided by 2 to the half power

    • 7 months ago
  21. Luigi0210
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    Well the 1/2 makes that 2 a rad 2: \[\frac{\sqrt{8}}{\sqrt{2}}\] Now what does \[\sqrt{8}\] simplify into?

    • 7 months ago
  22. izhangy
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    2√(2)

    • 7 months ago
  23. Luigi0210
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    Yup! \[\frac{2\sqrt{2}}{\sqrt{2}}\] Can you finish it?

    • 7 months ago
  24. izhangy
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    2, right?

    • 7 months ago
  25. Luigi0210
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    Mhm :)

    • 7 months ago
  26. izhangy
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    thanks bro

    • 7 months ago
  27. izhangy
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    do you know how to calculate average rate of change?

    • 7 months ago
  28. Luigi0210
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    Anytime. Average rate of change? As in calculus?

    • 7 months ago
  29. izhangy
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    yes :D

    • 7 months ago
  30. Luigi0210
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    Sorry, I haven't had calculus for a while :/ just open a new question and call Nincompoop, he's great at calculus

    • 7 months ago
  31. izhangy
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    ah alrighty thanks dood.

    • 7 months ago
  32. Luigi0210
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    Yup, and if he's not on call dan815

    • 7 months ago
  33. izhangy
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    kk

    • 7 months ago
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