UsukiDoll
  • UsukiDoll
Need help on this problem. see attachment
Mathematics
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chestercat
  • chestercat
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UsukiDoll
  • UsukiDoll
1 Attachment
UsukiDoll
  • UsukiDoll
|dw:1377671228491:dw|
UsukiDoll
  • UsukiDoll
@dumbcow

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More answers

UsukiDoll
  • UsukiDoll
@mathslover
dumbcow
  • dumbcow
\[c \int\limits _0 ^\infty e^{-3x} dx = 1\] \[-\frac{c}{3}|e^{-3x} _{0->\infty} = 1\] \[-\frac{c}{3}(e^{-\infty} - e^{0}) = 1\] \[c = 3\]
UsukiDoll
  • UsukiDoll
ohhhh improper integrals.
UsukiDoll
  • UsukiDoll
do I use the same function to get the f(1/2)-(f0)?
dumbcow
  • dumbcow
yes
UsukiDoll
  • UsukiDoll
|dw:1377673616300:dw|
dumbcow
  • dumbcow
remember c=3 and you dont need the other constant
UsukiDoll
  • UsukiDoll
|dw:1377673684883:dw|
UsukiDoll
  • UsukiDoll
|dw:1377673752426:dw|
UsukiDoll
  • UsukiDoll
|dw:1377673806805:dw|
dumbcow
  • dumbcow
forgot a negative |dw:1377673934135:dw|
UsukiDoll
  • UsukiDoll
would that be it since it didn't say equal to 1?
dumbcow
  • dumbcow
\[\int\limits _0 ^ {1/2}3e^{-3x} dx = 1-e^{-3/2} = 0.77687\]

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