anonymous
  • anonymous
If a ball is thrown in the air with a velocity 44 ft/s, its height in feet t seconds later is given by y = 44t − 16t2. (a) Find the average velocity for the time period beginning when t = 2 and lasting (i) 0.5 second. ft/s (ii) 0.1 second. ft/s (iii) 0.05 second. ft/s (iv) 0.01 second. ft/s
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
all of it
anonymous
  • anonymous
Average velocity is : \[V=\frac{ \Delta y }{ \Delta t }\]
anonymous
  • anonymous
You can elaborate on the formula a little more:\[V=\frac{ \Delta y }{ \Delta t }=\frac{ 44(t+\Delta t)-16(t+ \Delta t)^2-44t+16t^2 }{ \Delta t}=44-32t-16 \Delta t\] Before using this formula, make sure the ball is going up or down all the time in the interval. This can be checked finding the time of maximum height:44-32t=0--->t=44/32<2---> the ball has reached max height and is falling.

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