anonymous
  • anonymous
Find the four courners of the fundamental rectangle of the hyperbola x2/36 - y^2/49 = 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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dan815
  • dan815
|dw:1377703834902:dw|
anonymous
  • anonymous
Yes I did that! For my answer I got (6,0), (-6,0),(0,7) and (0,-7) does your answer match up?
dan815
  • dan815
|dw:1377703924761:dw|

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dan815
  • dan815
|dw:1377703987022:dw|
anonymous
  • anonymous
I'm not sure what that means!
dan815
  • dan815
|dw:1377704114127:dw|
dan815
  • dan815
whats the fundamental rectangle of a hyperbola
anonymous
  • anonymous
y^2/a^2 -x^2/b^2 = 1?
dan815
  • dan815
i mean what is this rectangle supposed to look like on the graph
dan815
  • dan815
there are they getting those points from
dan815
  • dan815
oh i see, here this tells you how they get those points
dan815
  • dan815
http://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.334131.html
dan815
  • dan815
1. The four corners of the fundamental rectangle of the hyperbola which opens right and left are are (a,b), (a,-b), (-a,b),(-a,-b)
dan815
  • dan815
|dw:1377704421621:dw|
anonymous
  • anonymous
WOOhoo! I got those answers too second time around!
anonymous
  • anonymous
does the hyperbola open up and down or right to left though?
anonymous
  • anonymous
@dan815 It looks like it opens up and down so wont the answer be a little different?
dan815
  • dan815
i dont know i didnt read that site
anonymous
  • anonymous
Yeah the picture you drew the hyperbola opens up and down which means the numbers would be (7,6), (7-6) (-7,6) and (6,7) I'm not forsure but read this website it says something like this http://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.334131.html
anonymous
  • anonymous
oops excuse me for the last one (-7,-6)
dan815
  • dan815
i think the rectangle has to pass through these 2 points|dw:1377704907853:dw|
dan815
  • dan815
no other way to pass through those 2 points, unless you draw the rectangle this way
anonymous
  • anonymous
but for the equation it's y^2/36 - x^2/49 because it opens upwards so wouldnt it just flip around the numbers (x,y) take your square roots and make it (7,6), (7-6) (-7,6) (-7,-6) It would still be a rectangle wouldn't it? Not sure just confused!
dan815
  • dan815
hold on if u want those points then the hyperbola wuid have to open right and left
dan815
  • dan815
ok i thought so this parabola looksl ike this actually
dan815
  • dan815
|dw:1377705172253:dw|
anonymous
  • anonymous
Ah okay! that makes sense because the equation they gave up is the right/left hyperbola x^2/36-y^2/49!
dan815
  • dan815
|dw:1377705217582:dw|
dan815
  • dan815
it would still be the same answer
dan815
  • dan815
|dw:1377705303103:dw|
anonymous
  • anonymous
yeah because the up and down one starts with y2, so I think everything is making sense now! So the final answer would be as above?
dan815
  • dan815
yeah read those points off the drawing
anonymous
  • anonymous
thank you for all your help!
dan815
  • dan815
yw

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