oxford422
6500=5000(1.042)^x



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Anickyan
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Find x?

oxford422
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yea

Anickyan
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Use a logarithm.

oxford422
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i got it to 13=10(1.042)^x

Anickyan
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Is it \(13 = 10 * 1.024^x\) ?

oxford422
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yea

oxford422
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i just dont remember how to solve for variables as exponents

Anickyan
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Do you know about logarithms?

oxford422
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its been a long summer maybe

Anickyan
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First, you must isolate \(1.024^x\)

KeithAfasCalcLover
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\[6500=5000(1.042)^x\]
\[\frac{6500}{5000}=1.042^x\]
\[1.3=1.042^x\]
\[log_{10}(1.3)=x*log_{10}(1.042)\]
\[\frac{log_{10}(1.3)}{log_{10}(1.042)}=x\]
\[x \dot{=}6.377\]

Anickyan
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Then, when you have \(1.024^x = y\), you do this to find \(x\):
\[x = \log_{1.024}(y)\]

Anickyan
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@KeithAfasCalcLover , you're not supposed to just give away the answer.

oxford422
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i just needed to see it