Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
Use a logarithm.
 one year ago

oxford422 Group TitleBest ResponseYou've already chosen the best response.0
i got it to 13=10(1.042)^x
 one year ago

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
Is it \(13 = 10 * 1.024^x\) ?
 one year ago

oxford422 Group TitleBest ResponseYou've already chosen the best response.0
i just dont remember how to solve for variables as exponents
 one year ago

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
Do you know about logarithms?
 one year ago

oxford422 Group TitleBest ResponseYou've already chosen the best response.0
its been a long summer maybe
 one year ago

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
First, you must isolate \(1.024^x\)
 one year ago

KeithAfasCalcLover Group TitleBest ResponseYou've already chosen the best response.1
\[6500=5000(1.042)^x\] \[\frac{6500}{5000}=1.042^x\] \[1.3=1.042^x\] \[log_{10}(1.3)=x*log_{10}(1.042)\] \[\frac{log_{10}(1.3)}{log_{10}(1.042)}=x\] \[x \dot{=}6.377\]
 one year ago

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
Then, when you have \(1.024^x = y\), you do this to find \(x\): \[x = \log_{1.024}(y)\]
 one year ago

Anickyan Group TitleBest ResponseYou've already chosen the best response.0
@KeithAfasCalcLover , you're not supposed to just give away the answer.
 one year ago

oxford422 Group TitleBest ResponseYou've already chosen the best response.0
i just needed to see it
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.