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oxford422 Group Title

6500=5000(1.042)^x

  • 11 months ago
  • 11 months ago

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  1. Anickyan Group Title
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    Find x?

    • 11 months ago
  2. oxford422 Group Title
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    yea

    • 11 months ago
  3. Anickyan Group Title
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    Use a logarithm.

    • 11 months ago
  4. oxford422 Group Title
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    i got it to 13=10(1.042)^x

    • 11 months ago
  5. Anickyan Group Title
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    Is it \(13 = 10 * 1.024^x\) ?

    • 11 months ago
  6. oxford422 Group Title
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    yea

    • 11 months ago
  7. oxford422 Group Title
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    i just dont remember how to solve for variables as exponents

    • 11 months ago
  8. Anickyan Group Title
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    Do you know about logarithms?

    • 11 months ago
  9. oxford422 Group Title
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    its been a long summer maybe

    • 11 months ago
  10. Anickyan Group Title
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    First, you must isolate \(1.024^x\)

    • 11 months ago
  11. KeithAfasCalcLover Group Title
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    \[6500=5000(1.042)^x\] \[\frac{6500}{5000}=1.042^x\] \[1.3=1.042^x\] \[log_{10}(1.3)=x*log_{10}(1.042)\] \[\frac{log_{10}(1.3)}{log_{10}(1.042)}=x\] \[x \dot{=}6.377\]

    • 11 months ago
  12. Anickyan Group Title
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    Then, when you have \(1.024^x = y\), you do this to find \(x\): \[x = \log_{1.024}(y)\]

    • 11 months ago
  13. Anickyan Group Title
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    @KeithAfasCalcLover , you're not supposed to just give away the answer.

    • 11 months ago
  14. oxford422 Group Title
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    i just needed to see it

    • 11 months ago
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