anonymous
  • anonymous
Explain why (3, 5) cannot be one of the vertices of a square drawn on the coordinate plane with a vertex at the origin.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AkashdeepDeb
  • AkashdeepDeb
Imagine it to be like this: If 3,5 IS A POINT on the square then! It will have 3 units to the right and 5 units at the top! And we know that the other vertex is at the origin so we could infer from that That The square would have a side of 3units AND a side of 5 units, which contradicts the original definition of a sqaure that states that a square has all sides equal!!! :D Understood why a square cannot have vertices at (3,5) AND the origin? :D
anonymous
  • anonymous
is that why they have(0,0)? ohh okay so it always has to be equal!
anonymous
  • anonymous
thanksssss

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AkashdeepDeb
  • AkashdeepDeb
:)

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