anonymous
  • anonymous
f(x) = Square root of quantity x plus seven.; g(x) = 8x - 11 Find f(g(x)).
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
f(g(x)) = 2Square root of quantity two x plus one. f(g(x)) = 8Square root of quantity x plus seven. - 11 f(g(x)) = 8Square root of quantity x minus four. f(g(x)) = 2Square root of quantity two x minus one.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1377713688014:dw|
CGGURUMANJUNATH
  • CGGURUMANJUNATH
can u tell me the answer ?

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More answers

anonymous
  • anonymous
The square root of 8x -4
anonymous
  • anonymous
But that's were I get stuck.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
s u are right :)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
tell me what is ur confusion ?
anonymous
  • anonymous
I have to choose from f(g(x)) = 2Square root of quantity two x plus one. f(g(x)) = 8Square root of quantity x plus seven. - 11 f(g(x)) = 8Square root of quantity x minus four. f(g(x)) = 2Square root of quantity two x minus one.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
c
anonymous
  • anonymous
But that means 8^ square root x-4
anonymous
  • anonymous
I'm going to go with A.
DebbieG
  • DebbieG
\[\Large \sqrt{(8x-11)+7}=\sqrt{8x-4}=\sqrt{4(2x-1)}=....?\] when you simplify that square root? :)
DebbieG
  • DebbieG
(e.g., when there is a perfect square under the sq root, you take its root and it gets to come outside.)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
exxplain me how ? "a"
CGGURUMANJUNATH
  • CGGURUMANJUNATH
d is also right.
DebbieG
  • DebbieG
Explain how it's c...?? lol
DebbieG
  • DebbieG
ONLY d is right. :)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
d and c are same.
DebbieG
  • DebbieG
\[\Large 2\sqrt{(2x-1)}=8\sqrt{(x-4)}....?\]
DebbieG
  • DebbieG
I don't think so.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
solve correctly before commenting.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1377715523192:dw|
DebbieG
  • DebbieG
Uhm, I'm not being snippy with you. If I'm wrong, please just politely explain where I'm wrong. I don't think the expressions in C and D are equivalent.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
did u get it now ?
DebbieG
  • DebbieG
Right. Now that's equivalent to the expression in C, how?
DebbieG
  • DebbieG
**I** said that above. **YOU** said that's the same as what's in C. I'm asking how.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
i'm sorry
DebbieG
  • DebbieG
YOU said: \(\Large 2\sqrt{(2x-1)}=8\sqrt{(x-4)}\) so explain how?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
i misread it.
DebbieG
  • DebbieG
's ok. :) I made at least 3 mistakes on the board in front of my classes today, it happens. :) lol
CGGURUMANJUNATH
  • CGGURUMANJUNATH
thanks.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
|dw:1377715814139:dw|
CGGURUMANJUNATH
  • CGGURUMANJUNATH
lol lol lol.
DebbieG
  • DebbieG
:)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
:)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
ONLY d is right.
CGGURUMANJUNATH
  • CGGURUMANJUNATH
r u clear with this @godhelpme .
amistre64
  • amistre64
back in my day we used number to write out math sentences ....
anonymous
  • anonymous
D?
CGGURUMANJUNATH
  • CGGURUMANJUNATH
s
CGGURUMANJUNATH
  • CGGURUMANJUNATH
only d
amistre64
  • amistre64
f(x) = Square root of quantity x plus seven. this is ambiguous since it doesnt use any grouping symbols ... \[\sqrt x+7\]or \[\sqrt{x+7}\]
CGGURUMANJUNATH
  • CGGURUMANJUNATH
is it very clear ?
anonymous
  • anonymous
Thanks I've got it now XD
DebbieG
  • DebbieG
I get what you're saying @amistre64 .... but I guess when I see "quantity of..." followed by an operator, I figure it's safe to assume that the "quantity" is around the operation? But you know what they say, about when you ASSume......... :)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
@amistre64 x plus seven. (quantity) so 2nd option is right no confusion please.
DebbieG
  • DebbieG
But it's true, when using only text, ( ) would still help avoid ambiguity.... e.g..... Square root of (x + 7) :)
CGGURUMANJUNATH
  • CGGURUMANJUNATH
u r right @DebbieG

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