anonymous
  • anonymous
derivative of 2/frthrt(x^3)
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what is frthrt?
anonymous
  • anonymous
fourth root :))
anonymous
  • anonymous
\[y=\frac{ 2 }{ \sqrt[4]{x^3}}=2x^{-\frac{ 3 }{ 4 }} \] and you must know that\[y=x^p \rightarrow y'=px^{p-1}\]

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anonymous
  • anonymous
\[\sqrt[b]{x^a} = x^{\frac{ a }{ b }}\]
anonymous
  • anonymous
thankyou so much @CarlosGP and @Euler271 much help thankyou!!
anonymous
  • anonymous
you are welcome
anonymous
  • anonymous
uhmm, @CarlosGP do i have to subtract -3/4 to 1? i remember my teacher said that once you got the derivative, you have to subtract its exponent by 1..
anonymous
  • anonymous
nope, p=-3/4 and p-1=-3/4-1=-3/4-4/4=-7/4
anonymous
  • anonymous
okay okay, thank you so much big help for our exams.. having trouble with calculus :( thank you :)))))
anonymous
  • anonymous
its ok

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