anonymous
  • anonymous
There is a linear homogeneous electric charge, along the semicircle of radius R (see figure below).
Physics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\lambda _{r} = \lambda _{0} = constant \] \[\lambda _{0} : charge density \] \[p = 2*R*Q / \pi \] A) Prove that the total charge is \[Q = \lambda _{0} * \pi* R\] B) Prove that the dipole moment from the coordinates origin , can be calculated with the expresion
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anonymous
  • anonymous
NOTE: The expresion of the point B) is p = 2*R*Q / \pi . Prove that you can calculate de dipole moment like this
dan815
  • dan815
hey so A) charge density is constant

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dan815
  • dan815
you know that dq = lamba dl and since lambda is constant we can do q=lambda * lenth length here is the top half circumference of the circle therefore q=lambda*pi * r
dan815
  • dan815
now the dipole momeny
dan815
  • dan815
oh umm if they want some more clear notation then
dan815
  • dan815
|dw:1377748165539:dw|
dan815
  • dan815
okay now for the dipole moment
dan815
  • dan815
can u give me definition of this dipole moment? is it the effect of all the electric field from the semi circle?
dan815
  • dan815
on the origin here

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