anonymous
  • anonymous
help with solving the equation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
this is what I have\[2^{x}+2^{-x}=5\] i multiply by 2^x and get \[4^{2x}+1=5(2^{x})\]
zpupster
  • zpupster
try looking like this 2^x + 1/2^x = 5
anonymous
  • anonymous
do the quadratic formula equal to 2^x I think this part im not sure so i have \[2^{x}=\frac{ 2\pm \sqrt{25-8} }{ 8 }\]

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anonymous
  • anonymous
so am I on the right path or no?
zpupster
  • zpupster
try to use a common denominator on the left
anonymous
  • anonymous
well can't i just multiply both sides by 2^x and still solve the left side the same sort of way you are?
zpupster
  • zpupster
look at this you have 4^x not 4^2x on the left
anonymous
  • anonymous
why just 4^x?
anonymous
  • anonymous
nvm i got it
anonymous
  • anonymous
it is suppose to be 2^2x not 4 because you keep the same base and add the exponents
zpupster
  • zpupster
2^2x = 4^x sorry was trying to help you and do something else here at home at same time

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