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 one year ago
Convert the following parametric equ'n into a cartesaion equ'n
x= squrt (t+1) y=t2 ,
So I don't know how to "eliminate" the t.
 one year ago
Convert the following parametric equ'n into a cartesaion equ'n x= squrt (t+1) y=t2 , So I don't know how to "eliminate" the t.

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SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1\[\begin{cases}x=\sqrt{t+1}\\y=t2\end{cases}\] There are two ways to eliminate the \(t\) here; solve for \(t\) in terms of \(y\) and plug it into the first equation, or solve for \(t\) in terms of \(x\) and plug it into the second equation. Either way works.

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0So its literally like a system of equation? I was taught with equations including cos and sin, so I was using the unit circle to eliminate t.

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1Kind of. The unit circle thing only works for some parametric equations. Let's try the second route: \[x=\sqrt{t+1}~~\Rightarrow~~x^2=t+1~~\Rightarrow~t=x^21\] Plugging this into the second equation, you get \[y=(x^21)2=x^23\]

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1For simple problems like this one, substitution is the way to go.

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0Alright, its weird , this is for Cal 3 and it feels like it's linear algebra/ grade 11 stuff. Anyway thanks!

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome!
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