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Convert the following parametric equ'n into a cartesaion equ'n
x= squrt (t+1) y=t2 ,
So I don't know how to "eliminate" the t.
 7 months ago
 7 months ago
Convert the following parametric equ'n into a cartesaion equ'n x= squrt (t+1) y=t2 , So I don't know how to "eliminate" the t.
 7 months ago
 7 months ago

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SithsAndGigglesBest ResponseYou've already chosen the best response.1
\[\begin{cases}x=\sqrt{t+1}\\y=t2\end{cases}\] There are two ways to eliminate the \(t\) here; solve for \(t\) in terms of \(y\) and plug it into the first equation, or solve for \(t\) in terms of \(x\) and plug it into the second equation. Either way works.
 7 months ago

MarcLeclairBest ResponseYou've already chosen the best response.0
So its literally like a system of equation? I was taught with equations including cos and sin, so I was using the unit circle to eliminate t.
 7 months ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
Kind of. The unit circle thing only works for some parametric equations. Let's try the second route: \[x=\sqrt{t+1}~~\Rightarrow~~x^2=t+1~~\Rightarrow~t=x^21\] Plugging this into the second equation, you get \[y=(x^21)2=x^23\]
 7 months ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
For simple problems like this one, substitution is the way to go.
 7 months ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Alright, its weird , this is for Cal 3 and it feels like it's linear algebra/ grade 11 stuff. Anyway thanks!
 7 months ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
You're welcome!
 7 months ago
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