anonymous
  • anonymous
Solve the system of the quadratic equation y=x^2-2x+2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
(x-2)(x-1)
anonymous
  • anonymous
equal it to zero
anonymous
  • anonymous
i would complete the square you will see two complex solutions

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anonymous
  • anonymous
\[x^2-2x+2=0\]subtract 2 from both sides \[x^2-2x=-2\] then take half of \(-2\) to get \(-1\) square it and get \(1\) and complete the square as \[(x-1)^2=-2+1=-1\]
anonymous
  • anonymous
take the square root to get \[x-1=\pm i\] and so \[x=1\pm i\]

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