anonymous
  • anonymous
Solve each inequality 8<2v-4<16
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
the idea is to isolate v
jim_thompson5910
  • jim_thompson5910
so we first add 4 to all sides then we divide all sides by 2
anonymous
  • anonymous
Wait ill tey to answer

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More answers

jim_thompson5910
  • jim_thompson5910
alright
anonymous
  • anonymous
6
jim_thompson5910
  • jim_thompson5910
good, here are the steps if you're curious \[\large 8 < 2v-4 < 16\] \[\large 8+4 < 2v-4+4 < 16+4\] \[\large 12 < 2v+0 < 20\] \[\large 12 < 2v < 20\] \[\large \frac{12}{2} < \frac{2v}{2} < \frac{20}{2}\] \[\large 6 < \frac{1v}{1} < 10\] \[\large 6 < 1v < 10\] \[\large 6 < v < 10\]
jim_thompson5910
  • jim_thompson5910
I'm sure you did all that
anonymous
  • anonymous
Yeah im right. But i did not that 1 i just cancel it out
jim_thompson5910
  • jim_thompson5910
that's ok, I put more steps than needed really to be really technical
anonymous
  • anonymous
-7d <_4d-3<_-1
jim_thompson5910
  • jim_thompson5910
hint: use the idea that x < y < z breaks up into x < y and y < z
anonymous
  • anonymous
How can i use that in this equation whats the y?
jim_thompson5910
  • jim_thompson5910
-7d <_4d-3<_-1 breaks up into -7d <_4d-3 and 4d-3<_-1
jim_thompson5910
  • jim_thompson5910
solve each for d
anonymous
  • anonymous
I dnt know how to solve this one its complicated
jim_thompson5910
  • jim_thompson5910
give it a shot
jim_thompson5910
  • jim_thompson5910
tackle each one on its own
anonymous
  • anonymous
Ill try
anonymous
  • anonymous
d>_d<_-4?
jim_thompson5910
  • jim_thompson5910
hmm that seems off
anonymous
  • anonymous
Dnt know pls explain thnx :)
jim_thompson5910
  • jim_thompson5910
what do you get when you solve -7d <_4d-3
anonymous
  • anonymous
-d
jim_thompson5910
  • jim_thompson5910
hint: -7d <_4d-3 -7d -4d <_ -3
anonymous
  • anonymous
d<_-3?
jim_thompson5910
  • jim_thompson5910
you're missing something on the left side
anonymous
  • anonymous
-3?
jim_thompson5910
  • jim_thompson5910
no -7d - 4d = ??
anonymous
  • anonymous
-11
anonymous
  • anonymous
How about the other side?
jim_thompson5910
  • jim_thompson5910
so we have -11d <_ -3 now divide both sides by -11 to isolate d, this will flip the inequality sign
anonymous
  • anonymous
<_ 3.66
anonymous
  • anonymous
>_ imean
jim_thompson5910
  • jim_thompson5910
leave it as a fraction
anonymous
  • anonymous
I got 3.6
jim_thompson5910
  • jim_thompson5910
leave it as a fraction to get d >= 3/11
jim_thompson5910
  • jim_thompson5910
now solve the other piece
anonymous
  • anonymous
Ow i got >_ 2d
jim_thompson5910
  • jim_thompson5910
solve 4d-3<_-1 for d
anonymous
  • anonymous
Yeah i put 3 in both sides
anonymous
  • anonymous
Then the answer was divided into 4 so i got 2
jim_thompson5910
  • jim_thompson5910
2/4 is not 2 though
anonymous
  • anonymous
Why
jim_thompson5910
  • jim_thompson5910
4/2 = 2 not the other way around
jim_thompson5910
  • jim_thompson5910
4/2 = 2 2/4 = ???
anonymous
  • anonymous
.5
jim_thompson5910
  • jim_thompson5910
or 1/2
jim_thompson5910
  • jim_thompson5910
so d <= 1/2
jim_thompson5910
  • jim_thompson5910
so all together, we know this d >= 3/11 and d <= 1/2 put together, the final answer is \[\large \frac{3}{11} \le d \le \frac{1}{2}\]
anonymous
  • anonymous
So ill combine and thats the final asnwer
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
This is the equation i cant understand
jim_thompson5910
  • jim_thompson5910
ok last one
anonymous
  • anonymous
6y-3<27 or -4y+2<-26 what ir means
jim_thompson5910
  • jim_thompson5910
you solve each inequality for y so what do you get when you solve 6y-3<27
anonymous
  • anonymous
Hold on a sec
anonymous
  • anonymous
Y<5
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
solve -4y+2<-26 for y
anonymous
  • anonymous
Y<-6
jim_thompson5910
  • jim_thompson5910
no that's incorrect
anonymous
  • anonymous
7?
anonymous
  • anonymous
-7?
anonymous
  • anonymous
Is that right?
jim_thompson5910
  • jim_thompson5910
it should be y > 7
jim_thompson5910
  • jim_thompson5910
so after solving 6y-3<27 or -4y+2<-26 , we get this y < 5 or y > 7
anonymous
  • anonymous
So thats the final answer?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
Thank you so much
jim_thompson5910
  • jim_thompson5910
you're welcome

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