If this calculation continued forever, what would you expect the answer to be:
1/3 + 1/9 + 1/27 + 1/81 + 1/243 + ...

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\[\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+...\] so you know how to add this up ?

no i dont

\[a+ar+ar^2+ar^3+ar^4+...=\frac{a}{1-r}\] use
\[a=r=\frac{1}{3}\]

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