anonymous
  • anonymous
solve 2sinxcosx=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
sin2x=0 2x=sin^-1(0)
anonymous
  • anonymous
then what...?
anonymous
  • anonymous
divide both sides by 2...

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anonymous
  • anonymous
wait
anonymous
  • anonymous
\(\sin x\) is 0 for angles of \(x=n\pi\), so \(\sin 2x\) is 0 for \(x=\dfrac{n\pi}{2}\).
anonymous
  • anonymous
would you go to 2x=sin^-1(0) +2 pi n 2x=0 + 2 pi n x=pi n?
anonymous
  • anonymous
whoa whoa you are making this much harder than it is
anonymous
  • anonymous
^^Right you don't even need to use the identity in the first place.
anonymous
  • anonymous
\[2\sin(x)\cos(x)=0\iff \sin(x)\cos(x)=0\iff \sin(x)=0\text { or } \cos(x)=0\]
anonymous
  • anonymous
the 2 out front is a red herring, ignore it this is rather easy right?
anonymous
  • anonymous
wait but u got x=pi n /2 and I got x= pi n?
anonymous
  • anonymous
where is cosine equal zero?
anonymous
  • anonymous
where is sine equal zero?
anonymous
  • anonymous
90 and 270 degrees 0 and 180 degrees
anonymous
  • anonymous
? IDK where this is taking me...

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