anonymous
  • anonymous
1
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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zepdrix
  • zepdrix
Have you tried multiplying the brackets? Remember how to FOIL? :)
anonymous
  • anonymous
I can multiply them, I have trouble with the conversions to sin and cos. Seeing it written out would be greatly beneficial
zepdrix
  • zepdrix
So when we multiply it all out we get this yes?\[\Large \sin x \color{#CC0033}{\sec x}+ \sin x\color{#3366CF}{\csc x}- \cos x \color{#CC0033}{\sec x}-\cos x \color{#3366CF}{\csc x}\]

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zepdrix
  • zepdrix
We'll want to apply our conversions to the red and blues.
zepdrix
  • zepdrix
\[\Large \color{#3366CF}{\csc x\quad=\quad \frac{1}{\sin x}} \qquad\qquad\qquad \color{#CC0033}{\sec x\quad=\quad \frac{1}{\cos x}}\]
anonymous
  • anonymous
So that gives (Sinx)(1/cosx)+(sinx)(1/sinx)-(cosx)(1/cosx)-(cosx)(1/sinx) ?
zepdrix
  • zepdrix
yah that looks right. Sooooo we can simplify those middle terms down really nicely, huh?
anonymous
  • anonymous
final answer is then tan x- cot x ???
zepdrix
  • zepdrix
Yay good job! \c:/

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