anonymous
  • anonymous
solve 2sinxcosx=0 sin2x=0 2x=sin^-1 (0) Is the soln. x=pi/n or x=pi n/2?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
oh, there's a typo... x=pi n or x=pi n /2
tkhunny
  • tkhunny
You an do it without alteration. sin(x) = 0 at x = 0 and pi cos(x) = 0 at x = pi/2 and 3pi/2 Or, you can use the transformation you selected. sin(2x) = 0 at 2x = 0, pi, 2pi, 3pi giving x = 0, pi/2, pi, 3pi/2 Isn't it interesting that mathematics works?!
anonymous
  • anonymous
so... you're saying that the latter, x=pi n /2 is the correct answer?

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anonymous
  • anonymous
\[0,\frac{\pi}{2},\pi,\frac{3\pi}{2},2\pi,...\] any place where either sine is zero or cosine is zero
anonymous
  • anonymous
if you want to abbreviate this you can write \[x=\frac{n\pi}{2},n\in \mathbb{Z}\]
anonymous
  • anonymous
oh... now I see what you were trying to tell me. hahaha but representing it would be pi n /2, correct?
anonymous
  • anonymous
oh, ok thank you so much! my firend gave me a wrong answer LOL
anonymous
  • anonymous
don't trust friends
anonymous
  • anonymous
:) hahaha ok i wont
anonymous
  • anonymous
lesson learned? :)
anonymous
  • anonymous
u r one of my favorite ppl on here~ hahaha keep at it!

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