megannicole51
  • megannicole51
find the exact area under f(x)=xe^(x^2) between x=0 and x=2.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dan815
  • dan815
iam here
dan815
  • dan815
HAVE NO FEAR I HAVE THE ANSWER
Luigi0210
  • Luigi0210
Ofc you are dan >.>

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More answers

dan815
  • dan815
hahahaha
megannicole51
  • megannicole51
lol
Luigi0210
  • Luigi0210
Well take it away.. as usual
dan815
  • dan815
|dw:1377754042866:dw|
dan815
  • dan815
so u want to find the area under some curve,
dan815
  • dan815
think about it like splittling up into small rectangulaer pieces
dan815
  • dan815
|dw:1377754101536:dw|
anonymous
  • anonymous
I ALMOST thought this integral couldn't;t be evaluated for a sec because of the exponential :P .
dan815
  • dan815
as the delta x goes to 0 you can think of it as dx, you keep adding the f(x)*dx, all under the graph to get the full area
dan815
  • dan815
|dw:1377754211607:dw|
dan815
  • dan815
|dw:1377754238784:dw|
dan815
  • dan815
if you dont know why i suddently said adding all the small pieces under the graph is the same as taking the integral
dan815
  • dan815
you should look up that proof!! form reimann sum rectangles to integral notation
dan815
  • dan815
this is where calculus gets interesting!! so u should know all this stuff inside and out
megannicole51
  • megannicole51
yeah i remember learning all of this last year but i cant remember the details of it lol
dan815
  • dan815
yeah i know most people dont worry about it!! but thats the real important stuff
megannicole51
  • megannicole51
okay:) so i was with you so far on the problem but theres no way were done lol
megannicole51
  • megannicole51
or are we
dan815
  • dan815
Ya its done
megannicole51
  • megannicole51
wow that was was more simple than i expected...thank you:)
Luigi0210
  • Luigi0210
@dan815 you're gonna be my teacher
dan815
  • dan815
ofcourse!! math is made to be simple!@
dan815
  • dan815
lol
dan815
  • dan815
u dont need me >_> u already know everything
Luigi0210
  • Luigi0210
Ofc you would think that dan :P

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