anonymous
  • anonymous
how do i find a point that is perpendicular to another line if I know what the equation of the first line is and i know what the slope is.
Trigonometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
say the given slope is 2/3 Any line perpendicular to the given line will have a slope of -3/2 One way to remember this is to think "flip the fraction and flip the sign" So.... Start with 2/3 (given slope) flip the fraction: 2/3 ----> 3/2 flip the sign: 3/2 ----> -3/2 Therefore, if the given line has a slope of 2/3, then the slope of any perpendicular line is -3/2
anonymous
  • anonymous
Im sorry I dont really understand this how do I do the whole problem so that I can do the next 3
jim_thompson5910
  • jim_thompson5910
what's the full problem again?

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jim_thompson5910
  • jim_thompson5910
what's all that you're given?
anonymous
  • anonymous
If the line h passes through the two points (1, 2) and (3, 6) This is the given information to solve the two problmes, here is the questions What is the slope of the line h passing through the two points? What is the equation of the line h passing through the two points? If line g passes through point (2, 2) and is perpendicular to the line h, then what is the equation of line g ?
jim_thompson5910
  • jim_thompson5910
how far did you get here?
jim_thompson5910
  • jim_thompson5910
were you able to find the slope of the line h?
anonymous
  • anonymous
i got that the equation of line h passing through is Y=2x
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
so the slope is 2 or 2/1
anonymous
  • anonymous
and the slpe is 2
jim_thompson5910
  • jim_thompson5910
so what's the perpendicular slope?
anonymous
  • anonymous
If line g passes through point (2, 2) and is perpendicular to the line h, then what is the equation of line g ? this is the one that I am having trouble with
jim_thompson5910
  • jim_thompson5910
if the slope is 2 or 2/1 then what's the perpendicular slope?
jim_thompson5910
  • jim_thompson5910
hint: look at my steps in my very first post
anonymous
  • anonymous
I really do not like math i am so slow to learn this stuff
jim_thompson5910
  • jim_thompson5910
that's ok
jim_thompson5910
  • jim_thompson5910
do you see how in my example (in my first post) where I went from 2/3 to -3/2 did that all make sense?
anonymous
  • anonymous
I was thinking that Y=-1/2X
jim_thompson5910
  • jim_thompson5910
the perpendicular slope is -1/2, that's a good start
jim_thompson5910
  • jim_thompson5910
so m = -1/2
jim_thompson5910
  • jim_thompson5910
the point line g goes through is (2,2) so this means that x = 2 and y = 2
anonymous
  • anonymous
but how do I figure this out IM not so good with all these formulas can you dumb this down a bit for me.
jim_thompson5910
  • jim_thompson5910
now we turn to y = mx+b and plug in m = -1/2, x = 2 and y = 2 y = mx + b y = (-1/2)x + b ... plug in m = -1/2 2 = (-1/2)*(2)+ b ... plug in x = 2 and y = 2 2 = (-1/2)*(2/1)+ b 2 = (-1*2)/(2*1)+ b 2 = -2/2 + b 2 = -1 + b 2 + 1 = b 3 = b b = 3 Therefore, m = -1/2 and b = 3 So the equation of line g is \[\large y = -\frac{1}{2}x + 3\]
jim_thompson5910
  • jim_thompson5910
let me know what you think
anonymous
  • anonymous
Im still trying to undersdand MX+B i know that those numbers have a funtion and you need to know what those are to move on right?
jim_thompson5910
  • jim_thompson5910
m is the slope of the line b is the y-intercept of the line
anonymous
  • anonymous
that is what my book says
jim_thompson5910
  • jim_thompson5910
x and y are variables they can be any number the value of y will depend on what x is
anonymous
  • anonymous
and you need to do some math to find the slope and I needed to know the other parts to do this problem right?
jim_thompson5910
  • jim_thompson5910
the usefulness of y = mx+b is that you can find the equation of any line if you know the slope and any point on the line
anonymous
  • anonymous
are you a teacher?
jim_thompson5910
  • jim_thompson5910
I'm a student learning to become one so yes and no
jim_thompson5910
  • jim_thompson5910
and yes, you need to figure out the slope before you can move on
anonymous
  • anonymous
I think I gave that to you right, which I got 2 for that
anonymous
  • anonymous
how did you find out y is that one of the four numbers that you use to plot the line?
jim_thompson5910
  • jim_thompson5910
what do you mean?
jim_thompson5910
  • jim_thompson5910
yes the original slope (ie the slope of h) is 2
anonymous
  • anonymous
I am trying to understand the whole equation I hate just getting the answers to a problem and not know how to solve it you know, i was wondering what Y is and how do you get the numbers for all the letters in this math problem.
anonymous
  • anonymous
ive been on google all night looking up how to solve for all these math problems and have been comming up with the right answers but have been struggling to understand them.
jim_thompson5910
  • jim_thompson5910
y is a variable and it is not assigned a fixed value like m or b are
jim_thompson5910
  • jim_thompson5910
when you say y = 2x, you are saying "for each x you plug in , you double the value to get y" so that means if you plug in x = 1, you get y = 2 (double 1 to get 2) when you plug in x = 13, you get y = 26 (double 13 to get 26)
jim_thompson5910
  • jim_thompson5910
this produces a bunch of points, you plot these points, then draw a line through them to graph y = 2x
anonymous
  • anonymous
My problem is im trying to do these in my head I dont have a calculator or graphing paper :(
jim_thompson5910
  • jim_thompson5910
well if you can't do them in your head, use pencil and paper
jim_thompson5910
  • jim_thompson5910
you can use google as a calculator ex: type in "2*3 + 10" into google without quotes and it will spit out the result like a calculator
anonymous
  • anonymous
i was trying to graph the lines to visualize them
jim_thompson5910
  • jim_thompson5910
and if you need a program to help you graph, I recommend geogebra http://www.geogebra.org/cms/en/
jim_thompson5910
  • jim_thompson5910
to graph the lines, you just need two points so one point on y = 2x is (1,2) another point on y = 2x is (2,4) plot the two points (1,2) and (2,4) and draw a straight line through them this will give you the graph of y = 2x
anonymous
  • anonymous
here is the next part to the questions that you have helped me with, If line F is parallel to the line H, and line F has Y-intercept 5, what is the equation of line F? can you walk me through all the steps and ill write them down as we go i really want to lean this type of math.
anonymous
  • anonymous
im guessing it is using the answer to the last question that you helped with.
jim_thompson5910
  • jim_thompson5910
what is the slope of line h
jim_thompson5910
  • jim_thompson5910
yes it all builds up
anonymous
  • anonymous
ok let me see what I have for that. I got 2 for that.
jim_thompson5910
  • jim_thompson5910
so m = 2
anonymous
  • anonymous
ok got it.
jim_thompson5910
  • jim_thompson5910
the y-intercept is given to be 5, so this means b = 5
jim_thompson5910
  • jim_thompson5910
so we go from y = mx+b to y = 2x + 5
jim_thompson5910
  • jim_thompson5910
that's the equation of line f
jim_thompson5910
  • jim_thompson5910
why is the slope 2? because parallel lines have equal slopes
jim_thompson5910
  • jim_thompson5910
slope of h is 2 line f is parallel to h so the slope of line f is also 2
anonymous
  • anonymous
do you have a aol sceen name i could add you to my list to ask another question some time?
anonymous
  • anonymous
im still writing down your words for the problem right now.
jim_thompson5910
  • jim_thompson5910
I don't use AOL messenger, but I do use yahoo messenger
anonymous
  • anonymous
oh i dont have that installed now. but you can email me at doclovett@yahoo.com
anonymous
  • anonymous
So Y and B are the same as 5? is this correct.
jim_thompson5910
  • jim_thompson5910
b is 5, y is a variable y is allowed to change
anonymous
  • anonymous
so y is an unknown
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
it represents any number pretty much at this point the same can be said for x
anonymous
  • anonymous
ok
anonymous
  • anonymous
damn now I have to deal with a triangle and COS and TAN
anonymous
  • anonymous
thanks for your help. I am trying to figure out angles with Sin A=15/17
jim_thompson5910
  • jim_thompson5910
check out this page http://openstudy.com/updates/521ef027e4b0750826e0c91a I think you (zombiebacon) and the user jaidyn206 are taking the same course. I could be wrong.
jim_thompson5910
  • jim_thompson5910
so you guys can set up a study session if that is true
anonymous
  • anonymous
yeah she is in my class im talking to her in aim she is ahead of me in the class on different questions.
jim_thompson5910
  • jim_thompson5910
I gotcha
anonymous
  • anonymous
what does sin A=15/17 mean
anonymous
  • anonymous
i just wasted a few min figuring out degrees in angles for nothing didn't I?
jim_thompson5910
  • jim_thompson5910
if you have a right triangle that looks like this |dw:1377760654037:dw|
jim_thompson5910
  • jim_thompson5910
then the sine of the angle A is equal to the opposite side (15) over the hypotenuse 17 ie, sin(A) = 15/17
jim_thompson5910
  • jim_thompson5910
no I don't think you wasted your time
anonymous
  • anonymous
how do I draw a picture to show you
jim_thompson5910
  • jim_thompson5910
use the draw button below the text box
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
that works
anonymous
  • anonymous
i attached the jpg of the triangle sin is A=15/17
jim_thompson5910
  • jim_thompson5910
ok so what's question referring to the picture?
anonymous
  • anonymous
what is the length of side a?
jim_thompson5910
  • jim_thompson5910
sin(A) = 15/17 tells us that the opposite side is 15 (the side opposite angle A) so a = 15
anonymous
  • anonymous
I have not read what sin means yet so that is where I am at on that.
jim_thompson5910
  • jim_thompson5910
17 is the hypotenuse, which is opposite the 90 degree angle the hypotenuse is always the longest side
jim_thompson5910
  • jim_thompson5910
so c = 17
jim_thompson5910
  • jim_thompson5910
I recommend reading up on that lesson
anonymous
  • anonymous
last week we learned about a^=B^=c^ and i was trying to understand that im sorry for the dumb retricequestions here but I have done nothing but struggle this whole moth with this class.
jim_thompson5910
  • jim_thompson5910
they're not dumb
jim_thompson5910
  • jim_thompson5910
I think you meant to say a^2 + b^2 = c^2 no?
anonymous
  • anonymous
yes the squared
jim_thompson5910
  • jim_thompson5910
that's the pythagorean theorem
anonymous
  • anonymous
we were learning about the length of the legs and bases and finding out the missing piece by using that equation
jim_thompson5910
  • jim_thompson5910
so if you have a right triangle, and you only knew 2 of the 3 sides, you can use the pythagorean theorem to find the missing side
anonymous
  • anonymous
I ws trying to use that for these last questions
jim_thompson5910
  • jim_thompson5910
what information is given? what do you know so far about the sides?
anonymous
  • anonymous
For question 14 and 20, refer to the right triangle Δ ABC with sides a, b, and c. If sin A = 15/17
jim_thompson5910
  • jim_thompson5910
what are a and c
anonymous
  • anonymous
using the picture I sent you and this we have to answer our questions.
jim_thompson5910
  • jim_thompson5910
I know, what are the values of a and c
anonymous
  • anonymous
unknown.
anonymous
  • anonymous
14. What is the length of side a? 14. A) 15 B) 8 C) 17 d) 10 15. What is the length of side c? 15. A) 15 B) 8 C) 17 d) 10 16. What is the length of side b? 16. A) 15 B) 8 C) 17 d) 10 17. What is the measurement of ∠Α? 17. Α) 61.930 Β) 28.070 C) 64.800 D) 25.200 18. What is the measurement of ∠B? 18. A) 61.930 Β) 28.070 C) 64.800 D) 25.200 19. What is cos A? 19. A) 0.47 B) 0.53 C) 0.88 D) 2.13 20. What is tan A? 20. A) 1.875 B) 2.125 C) 1.13 D) 0.53
anonymous
  • anonymous
those are the questions and im not even supposed to post them on any site or i will get in trouble.
anonymous
  • anonymous
but im really struggleing to understand this
jim_thompson5910
  • jim_thompson5910
why can't you post them?
anonymous
  • anonymous
my school made me sign a paper for all materials so that they can not be posted on the internet so people can't cheat and just get the answers.
jim_thompson5910
  • jim_thompson5910
I see
anonymous
  • anonymous
I am actually trying to learn this stuff and there are some guys that just cheat and look up the ansers on the net.
anonymous
  • anonymous
we also sign an acidemic dishonesty policy paper.
anonymous
  • anonymous
this class is costing me 5000 dollars and I really do not ant to fail it.
jim_thompson5910
  • jim_thompson5910
these are the same questions jaidyn206 just went through have you asked jaidyn206 for help?
anonymous
  • anonymous
I dont want to get just the answers from her.
jim_thompson5910
  • jim_thompson5910
no I'm not saying that, like I'm saying ask her questions and such
anonymous
  • anonymous
we are both very new to this type of math and she is having trouble walking me through it since she is unsure of it herself.
jim_thompson5910
  • jim_thompson5910
alright
jim_thompson5910
  • jim_thompson5910
which side is opposite angle A
anonymous
  • anonymous
ok oppisite of anble A is little a right.
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
because the longest ine the hypotanuse is a
jim_thompson5910
  • jim_thompson5910
sine is opposite over hypotenuse, so... sin(A) = 15/17 means that a =15 and c = 17 the opposite side is a the hypotenuse is c
anonymous
  • anonymous
and it is also the base i believe.
anonymous
  • anonymous
the little bulb just lit up in my head just now :D
jim_thompson5910
  • jim_thompson5910
that's great
jim_thompson5910
  • jim_thompson5910
glad it did
jim_thompson5910
  • jim_thompson5910
use these values of a and c to find b
anonymous
  • anonymous
so 17 the legnth is 17 of side c
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
now here is where i get confused are they using inches or what for 15 and 17?
jim_thompson5910
  • jim_thompson5910
don't worry about the units
anonymous
  • anonymous
I know that inside the triangle it is supposed to be 180 degrees
jim_thompson5910
  • jim_thompson5910
a = 15 b = unknown c = 17
jim_thompson5910
  • jim_thompson5910
a^2 + b^2 = c^2 15^2 + b^2 = 17^2 solve for b
anonymous
  • anonymous
now how to i use this to answer the question are we using degrees to answer this?
jim_thompson5910
  • jim_thompson5910
we're finding the side length b, not the angle B
anonymous
  • anonymous
oh snap, ok
jim_thompson5910
  • jim_thompson5910
so we don't need to worry about degrees
anonymous
  • anonymous
because i did the angles and it comes up to angle B is 15 degrees angle C is 90 degrees and angle A is 75 degrees.
anonymous
  • anonymous
I dont need any of that do I?
jim_thompson5910
  • jim_thompson5910
that's a bit off
jim_thompson5910
  • jim_thompson5910
angle C is 90 degrees though, that's correct
jim_thompson5910
  • jim_thompson5910
A and B are off though
anonymous
  • anonymous
289-225=64 and that squared is 8 right?
anonymous
  • anonymous
so I should have 8 as my answer.
jim_thompson5910
  • jim_thompson5910
b = 8 is correct
jim_thompson5910
  • jim_thompson5910
so the 3 sides are: a = 15 b = 8 c = 17
anonymous
  • anonymous
my angles are angle A is 62, angle B is 28 and angle c is 90 do I use these to answer the questions now?
anonymous
  • anonymous
to find the measurement of A do i just add A,C and A,B?
jim_thompson5910
  • jim_thompson5910
you rounded too far, but you have the right idea
anonymous
  • anonymous
doesnt it have to equal 180 degrees?
jim_thompson5910
  • jim_thompson5910
yes the 3 angles have to add up to 180 degrees
jim_thompson5910
  • jim_thompson5910
but angle A isn't exactly 62 degrees
anonymous
  • anonymous
the closest answer to mine is 61.93
jim_thompson5910
  • jim_thompson5910
that's the correct answer hopefully you see how to get it
anonymous
  • anonymous
but how do you get the decimal when i was getting whole numbers that is what is messing me up?
jim_thompson5910
  • jim_thompson5910
how did you get 62?
anonymous
  • anonymous
Im using a plastic protractor and paper to get my answers.
jim_thompson5910
  • jim_thompson5910
i see
anonymous
  • anonymous
the half moon thing is called a protractor right?
jim_thompson5910
  • jim_thompson5910
yes it is
anonymous
  • anonymous
it only has lines and not decimals on it.
anonymous
  • anonymous
and whole numbers.
jim_thompson5910
  • jim_thompson5910
on this page here http://openstudy.com/study#/updates/521ef027e4b0750826e0c91a I explain how to find angle A
anonymous
  • anonymous
are you still there it says i lost connection?
jim_thompson5910
  • jim_thompson5910
yeah I am
jim_thompson5910
  • jim_thompson5910
look on that page and I explain how to find A
anonymous
  • anonymous
well when i did my angles with my protractor it was within the margin for the answers on the paper for me and I am picking the closestes.
jim_thompson5910
  • jim_thompson5910
on that page, I explain how to use google as a calculator to get the answer
jim_thompson5910
  • jim_thompson5910
there's no need to use a protractor keep in mind that the figure is usually NOT to scale
jim_thompson5910
  • jim_thompson5910
so it's a very bad idea to use a protractor, but I can see why you're using it
anonymous
  • anonymous
Im not that good at math so I used the protractor and drew it on paper to figure out the answer and got the closest to it.
jim_thompson5910
  • jim_thompson5910
well you can't rely 100% on the image alone
anonymous
  • anonymous
but since they are not whole numbers i need to look at the math style you showed me.
jim_thompson5910
  • jim_thompson5910
yes look that page over once more
anonymous
  • anonymous
ok how do I do this without a calculator I dont have one of those just the windows one.
jim_thompson5910
  • jim_thompson5910
its ok, google acts like a calculator
jim_thompson5910
  • jim_thompson5910
so even if you don't have one, you can have access to a free one
anonymous
  • anonymous
that is cool
jim_thompson5910
  • jim_thompson5910
sin(A) = 15/17 A = arcsin(15/17)
jim_thompson5910
  • jim_thompson5910
type "arcsin(15/17) in degrees" without quotes into google to get https://www.google.com/search?q=arcsin%2815%2F17%29+in+degrees&ie=UTF-8
anonymous
  • anonymous
OK thanks for the help I am going to get some rest I need to get up and work on my paper tomorrow.
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
do i need to close this thread
jim_thompson5910
  • jim_thompson5910
its ok, either way is fine usually yes, you are supposed to close a question when you are done with it
anonymous
  • anonymous
ok i will close it thank you for your help. good night.
jim_thompson5910
  • jim_thompson5910
you're welcome, good night

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