anonymous
  • anonymous
Hey, can someone please help me solve 4^2x - 5 x 4^x + 5 = 0 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[4^{2x} - 5\times4^{x} + 5 = 0\] - I tried updating the orignal post but it didn't work so here is the equation
anonymous
  • anonymous
4^x = t
anonymous
  • anonymous
helps ?

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cwrw238
  • cwrw238
4^2x - 5 x 4^x = 0 4^2x = 5 x 4^x take logs of both sides: ln 4^2x = ln 5 * 4^x
anonymous
  • anonymous
Is it possible to do it without logarithms? We have not yet done logarithms in class so it may give me bonus marks for answering using logarithms I don't think that is how it is meant to be solved
anonymous
  • anonymous
you have to substitute 4^x = t then your equation will become: t^2 -5t +5 = 0
anonymous
  • anonymous
Ah okay, that seems more like what we are doing, thanks for the help :)
anonymous
  • anonymous
now if indeed t will be something nice youll be able to find x without using logs
anonymous
  • anonymous
So then just factorise and solve that - I will need to use quadratic formula though won't I because I can not see anyway to get that factorised
anonymous
  • anonymous
yes
anonymous
  • anonymous
Cool, thanks for the help :)
anonymous
  • anonymous
i guess youll have to use logs since you wont get nice numbers.
anonymous
  • anonymous
My bad, I typed the question wrong accidently. It is plus 4 not plus 5 so therefore it does give me good numbers :P
anonymous
  • anonymous
Becomes (t-4)(t-1)
anonymous
  • anonymous
oh so solutions are obvious :)
anonymous
  • anonymous
Yep :P I had the question right the first time and when I tried to update using the formula thing I changed to a 5 instead of a 4 by mistake

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