anonymous
  • anonymous
What are the exact solutions of x2 − 5x − 7 = 0? x = the quantity of negative 5 plus or minus the square root of 3 all over 2 x = the quantity of 5 plus or minus the square root of 3 all over 2 x = the quantity of negative 5 plus or minus the square root of 53 all over 2 x = the quantity of 5 plus or minus the square root of 53 all over 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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DebbieG
  • DebbieG
What do you get when you factor that trinomial?
anonymous
  • anonymous
idk
skullpatrol
  • skullpatrol
Have you seen the "quadratic formula?"

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More answers

DebbieG
  • DebbieG
It's just "un-FOILing". You need to write \(x^2 − 5x − 7 \) as a product (multiplication) of two binomials: \(\Large x^2 − 5x − 7 =(....?....)(....?....)\) so you need to figure out what goes in the ( )'s. Since the trinomial starts with an \(x^2\) without a coefficient in front of it, you KNOW it has to be: \(\Large x^2 − 5x − 7 =(x\pm ?)(x\pm ?)\) So all you need is to figure out the LAST terms, and the signs in the middle.
DebbieG
  • DebbieG
oh wait, may bad.... @skullpatrol is right. Need the QF on this one.
DebbieG
  • DebbieG
*my
DebbieG
  • DebbieG
I hadn't looked at the answers... lol.
anonymous
  • anonymous
still don't get it
DebbieG
  • DebbieG
You have \(\Large x^2 − 5x − 7 =0\) That's of the form \(\Large ax^2 +bx +c =0\) For YOUR equation, what is a, b and c? a= ? b= ? c= ?
anonymous
  • anonymous
okay
skullpatrol
  • skullpatrol
|dw:1377774511799:dw|
anonymous
  • anonymous
okay
skullpatrol
  • skullpatrol
Please fill in what goes where the question marks are: a= ? b= ? c= ?
anonymous
  • anonymous
a=1 b=-5 c=-7
skullpatrol
  • skullpatrol
https://www.khanacademy.org/math/trigonometry/polynomial_and_rational/quad_formula_tutorial/v/using-the-quadratic-formula
anonymous
  • anonymous
yeah i dont get it
skullpatrol
  • skullpatrol
Did you watch the entire video?
anonymous
  • anonymous
yep
anonymous
  • anonymous
hello anyone there
skullpatrol
  • skullpatrol
Substitute the values of a, b, and c into the formula.
DebbieG
  • DebbieG
\[\Large x=\frac{ -b\pm \sqrt{b^2-4ac} }{ 2a}\] Plug 'n chug.
skullpatrol
  • skullpatrol
Substitute and evaluate.
anonymous
  • anonymous
hey girl wanna suck my mushroom tip??
anonymous
  • anonymous
no
anonymous
  • anonymous
can someone because i am confuse
anonymous
  • anonymous
the answer is A right
DebbieG
  • DebbieG
No. How did you compute the roots? show your work, and we can tell you where you went wrong.
anonymous
  • anonymous
|dw:1377820609182:dw| |dw:1377820679582:dw|
DebbieG
  • DebbieG
|dw:1377820804125:dw|
DebbieG
  • DebbieG
Mostly sign issues: First, It's -b, so -(-5)=5 Then it's b^2 = (-5)^2 = 25 then, -4ac=-4(1)(-7)=+28 Your setup was mostly OK, just some issues in the evaluation.
anonymous
  • anonymous
so it B @DebbieG
DebbieG
  • DebbieG
What makes you say B, from what I showed you above? Did you understand where your computation errors in the formula are?
DebbieG
  • DebbieG
|dw:1377821691793:dw| The final solution is almost completely done for you there ^^
anonymous
  • anonymous
its D
anonymous
  • anonymous
I am right @DebbieG
DebbieG
  • DebbieG
Yes, it's D.
anonymous
  • anonymous
yeah thank you

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