What are the exact solutions of x2 − 5x − 7 = 0?
x = the quantity of negative 5 plus or minus the square root of 3 all over 2
x = the quantity of 5 plus or minus the square root of 3 all over 2
x = the quantity of negative 5 plus or minus the square root of 53 all over 2
x = the quantity of 5 plus or minus the square root of 53 all over 2
Stacey Warren - Expert brainly.com
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It's just "un-FOILing". You need to write \(x^2 − 5x − 7 \) as a product (multiplication) of two binomials:
\(\Large x^2 − 5x − 7 =(....?....)(....?....)\)
so you need to figure out what goes in the ( )'s. Since the trinomial starts with an \(x^2\) without a coefficient in front of it, you KNOW it has to be:
\(\Large x^2 − 5x − 7 =(x\pm ?)(x\pm ?)\)
So all you need is to figure out the LAST terms, and the signs in the middle.
oh wait, may bad.... @skullpatrol is right. Need the QF on this one.
I hadn't looked at the answers... lol.
still don't get it
You have \(\Large x^2 − 5x − 7 =0\)
That's of the form \(\Large ax^2 +bx +c =0\)
For YOUR equation, what is a, b and c?
Please fill in what goes where the question marks are: