If this circuit is used to energize 1-H coil with 1 A of current...?
then allows the inductor to discharge through a 2 ohm resistor. how do determine the time constant and resistor current after the switch is opened for 1 second? I think i would do T=L/R for the time constant but i'm not sure
Stacey Warren - Expert brainly.com
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|dw:1377781499336:dw|. Your equation for the time constant (tau) is correct. The time constant = 1 H/2 Ohm or 1/2 second.
The following assumption is made, the internal resistance of the inductor is zero, and the switch has been closed for some length of (more than 2.5 seconds) so that the current is totally going thru the inductor and that is given as 1 Amp. When the switch is opened, the counter EMF (which is now the opposite polarity) causes a current to go thru the 2 Ohm