anonymous
  • anonymous
If this circuit is used to energize 1-H coil with 1 A of current...? then allows the inductor to discharge through a 2 ohm resistor. how do determine the time constant and resistor current after the switch is opened for 1 second? I think i would do T=L/R for the time constant but i'm not sure http://static.panoramio.com/photos/medium/95401143.jpg
Physics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Fifciol @radar
radar
  • radar
|dw:1377781499336:dw|. Your equation for the time constant (tau) is correct. The time constant = 1 H/2 Ohm or 1/2 second.
radar
  • radar
The following assumption is made, the internal resistance of the inductor is zero, and the switch has been closed for some length of (more than 2.5 seconds) so that the current is totally going thru the inductor and that is given as 1 Amp. When the switch is opened, the counter EMF (which is now the opposite polarity) causes a current to go thru the 2 Ohm resistor.

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radar
  • radar
|dw:1377782202279:dw||dw:1377782247236:dw| The current will instead be a function of the Time Constant tau and the initial current.|dw:1377782681496:dw|
radar
  • radar
For my own edification, what course are you taking?
anonymous
  • anonymous
I'm forcefully taking an Electricity course...
anonymous
  • anonymous
The time constant would be 0.5 s right?
radar
  • radar
yes .5 second or 1/2 second.

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