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I am looking for the y-intercept so this is what i have so far:
y= mx+b 4= 2/-3(-2)+b
then its 4= -4/-3 +b no idk what to do
this site helps sometimes try it http://www.wolframalpha.com/
but if you want an explanation ask someone
it gave me 4= b+ 4/3 which is 8/3
now how do i use the slope 2/-3 and b which is 8/3 to make an equation of the line in point-slope form
ok you have 4 = -2/3 (-2) + b 4 = 4/3 + b 4 4 12 -4 8 -- - --- = ----- = ------ 1 3 3 3 so b = 8/3
now just plug in on formula y = mx + b y = -2/3x + 8/3
noo i need point slope formula.
"2.Determine the equation of the line in point-slope form"
y - y1 = m(x - x1) (this formual ?)
then you have m = -2/3 and (x,y) could be any known point you have point (-2,4) so it is y - 4 = -2/3(x + 2)
so.. y-4= -2/3 x then what
If they want point - slope form, you do not need to first find y= mx + b (slope-intercept form) instead, find the slope, which you did and then pick one of the points, and use that point in \[ y - y_1= m(x-x_1) \]
y-4= -2/3 x + -4/3 right?
ohh so i did an extra step woops
Don't distribute. point-slope form is just \[ y - y_1= m(x-x_1) \] leave it that way
r u sure
is just y - 4 = -2/3(x + 2)
y - y1 = m(x - x1) do not distribute...just leave it , parenthesis and all
i have a few more questions im gonna put the next one
point-slope form is not very useful (for plotting for example) but it is easier to write down (less algebra).
my next one is Determine the equation of the line, in slope-intercept form
the points are:
(-5,6) and (-8,8)
this one is y = mx + b which you have done already first find the slope, then solve for b
for slope i got 2/-3
so i plug in a point, and the slope, to solve for b?
ok ill use (-5,6)
ok i got 6= -10/-3 +b
so that's like the same as 6= 10/3 +b right
yes. now add -10/3 to both sides
10/3 u mean
6= 10/3 +b add -10/3 to both sides
because you want 10/3 - 10/3 = 0 so you get 0+b on the right side
wait wait ur confusing me, look what ur writing. first u write 10/3 then u write -10/3.. which is it?
here is what you did: ok i got 6= -10/-3 +b so that's like the same as 6= 10/3 +b right yes, that is correct: 6 = 10/3 + b now to solve for b, add -10/3 to both sides
see u did it again
u wrote "now to solve for b, add -10/3 to both sides" do u see the problem here?
but just before you wrote 6= 10/3 +b
y would i add -10/3 to both sides if we just made the fraction simpler by taking away the negatives?
do i add or subtract
if would have been less confusing if u said subtract 10/3 from both sides
so now whats 6 - 10/3 ?
you agree we started with y = - 2/3 x + b you picked point (-5,6) and got 6 = - 2/3 * -5 + b which becomes 6 = 10/3 + b so far, so good. now add -10/3 to both sides. Can you do that ?
to do fractions, you need a common denominator. in this case, 3 to get a denominator of 3 for 6, multiply 6 times 3/3 you get 18/3 now you can do the fractions
so b is 18/3 ??
you should get b= 6 - 10/3 change 6 to 18/3 b= 18/3 - 10/3 to add or subtract fractions with the same bottom, add or subtract the tops 18 -10 = 8 and put that number over the common denominator
It looks like all the points are ending up on the same line y= -2/3 x + 8/3 looks familiar
because they are. i made it that way
we had to pick three points and make them be in the same line as (1,2) the "launch area" for a project.
and then you have to find the different ways to write an equation of a line: standard, point-slope, point-interecept ?