danmac0710
  • danmac0710
A tricky little modulus (absolute value) equation. Any ideas please?: abs(2x+3) = 3 * abs(x) -1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
looks simple enough ...
amistre64
  • amistre64
where are your vertexes located?
amistre64
  • amistre64
if you can determone your vertexes, you can redefine the abs function into its parts and just focus on the intersection of 2 lines |dw:1377790697620:dw|

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danmac0710
  • danmac0710
Thanks for that hint.... working on it!
danmac0710
  • danmac0710
Do you always do these ones graphically?
amistre64
  • amistre64
its prolly not necessary, but i work better with a visual ... you could just divvy it up into intervals to test the 4 line equations that make it up ...
amistre64
  • amistre64
from -inf to -3/2; we play with: -(2x+3) = -3x-1 from -3/2 to 0; we play with: (2x+3) = -3x-1 from 0 to inf; we play with: (2x+3) = 3x-1
amistre64
  • amistre64
spose its only 3 setups not 4
danmac0710
  • danmac0710
cheers man. That's helpful. Never done these type before.
phi
  • phi
that is a nice visual. if you do algebra, you have 4 cases: drop the abs value on both expressions + + negate the left expression, - + negate the right expression + - and negate both - - from the picture we see we will get 2 "non-solutions" |dw:1377791490734:dw|
danmac0710
  • danmac0710
thanks guys - very helpful
amistre64
  • amistre64
good luck ;)

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